two
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
Yes. The charge on Na (sodium) ions is 1+ and the charge on a SO4 (sulfate) ion is 2-. So to balance out the charges 2 sodium ions are needed for every sulfate ion.
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Na2S
Yes, Na+ can only exist as an ion in a solution and, in the body, ions in solutions are called electrolytes.
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
The principal species in Na2SO4 are sodium ions (Na+) and sulfate ions (SO4 2-).
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
In Na2SO4, there are a total of 3 ions present: 2 Na+ ions and 1 SO4^2- ion. The formula indicates the ratio of ions present in the compound.
The anion (SO4)2- is divalent; the cation Na+ is monovalent.
Sodium is the cation (+1 charge), sulfate is the anion (-2 charge) The chemical formula tells us there are two sodium ions (Na2) and one sulfate (SO4) ion.
Na+ and Cl- are spectator ions.
1 mol Na2SO4 will dissociate to 2 mol Na+ and 1 mol SO42- Therefore 0.350 M Na2SO4 will dissociate to 0.350*2 = 0.700 mol Na+ and 0.350*1 = 0.350 mol SO42- Therefore the total concentration of ions is 0.700 mol + 0.350 mol = 1.050 mol.
Dissolving in water (aq):Na2SO4 --> 2(Na+)aq + (SO42-)aq
The van't Hoff factor for Na2SO4 is 3, as it dissociates into 3 ions when dissolved in water: 2 Na+ ions and 1 SO4 2- ion.
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
The pH of a solution of Na2SO4 would be around 7, which is considered neutral. This is because Na2SO4 is a salt that dissociates completely in water to form Na+ and SO4 2- ions, which do not have a significant effect on the pH of the solution.