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Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
Yes. The charge on Na (sodium) ions is 1+ and the charge on a SO4 (sulfate) ion is 2-. So to balance out the charges 2 sodium ions are needed for every sulfate ion.
When 0.500 mol of Na2SO4 dissolves in water, it dissociates into 2 moles of Na⁺ and 1 mole of SO4²⁻ for every mole of Na2SO4. Therefore, from 0.500 mol of Na2SO4, there will be 1.000 mol of Na⁺ (2 × 0.500 mol) and 0.500 mol of SO4²⁻. When diluted to 1.33 L, the concentrations are calculated as follows: [Na⁺] = 1.000 mol / 1.33 L ≈ 0.751 M and [SO4²⁻] = 0.500 mol / 1.33 L ≈ 0.376 M.
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Na2SO4 is not a molecular formula because it represents an ionic compound, sodium sulfate. In ionic compounds, the elements are held together by ionic bonds rather than sharing electrons in covalent bonds like in molecular compounds. The formula Na2SO4 indicates that there are two sodium ions (Na+) for every sulfate ion (SO4^2-).
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
The principal species in Na2SO4 are sodium ions (Na+) and sulfate ions (SO4 2-).
In Na2SO4, there are a total of 3 ions present: 2 Na+ ions and 1 SO4^2- ion. The formula indicates the ratio of ions present in the compound.
The anion (SO4)2- is divalent; the cation Na+ is monovalent.
Sodium is the cation (+1 charge), sulfate is the anion (-2 charge) The chemical formula tells us there are two sodium ions (Na2) and one sulfate (SO4) ion.
Na+ and Cl- are spectator ions.
1 mol Na2SO4 will dissociate to 2 mol Na+ and 1 mol SO42- Therefore 0.350 M Na2SO4 will dissociate to 0.350*2 = 0.700 mol Na+ and 0.350*1 = 0.350 mol SO42- Therefore the total concentration of ions is 0.700 mol + 0.350 mol = 1.050 mol.
The van't Hoff factor for Na2SO4 is 3, as it dissociates into 3 ions when dissolved in water: 2 Na+ ions and 1 SO4 2- ion.
Dissolving in water (aq):Na2SO4 --> 2(Na+)aq + (SO42-)aq
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
The pH of a solution of Na2SO4 would be around 7, which is considered neutral. This is because Na2SO4 is a salt that dissociates completely in water to form Na+ and SO4 2- ions, which do not have a significant effect on the pH of the solution.