If the voltage in your vacuum is 120 then you divide the Wattage by the Voltage to get 3 amps.
Watts is volts times amps, so 12 x 30 = 360 watts
The conversion of watts to amps at a fixed voltage is governed by the equation Amps = Watts/Volts for example 12 watts/12 volts = 1 amp for a US example, a food mixer with a 400 watt motor on a 120 volt supply 400/120 = 3.33amps, fit a 5amp fuse
"Volt" is a unit of potential difference. "Joule" is a unit of energy. There is no direct conversion from one to the other. -- If a 2-ohm resistor is connected to a 5-volt battery, then the current through the resistor is volts/ohms = 2.5 amperes. -- The power supplied by the battery and dissipated by the resistor is (volts) x (current) = 12.5 watts. -- "12.5 watts" means "12.5 joules of energy every second".
On a 120 volt supply, up to 360 watts. On a 240 volt supply, up to 720 watts.
To convert kVA to amps, you need to also know the voltage. If we assume a standard voltage of 480V, then 300 kVA would be approximately 360 amps. This is calculated by dividing the kVA by the voltage and then converting to amps using the formula: Amps = (kVA * 1000) / (1.732 * Volts) where 1.732 is the square root of 3.
3 bulb can be connected..............................
Watts is volts times amps, so 12 x 30 = 360 watts
The conversion of watts to amps at a fixed voltage is governed by the equation Amps = Watts/Volts for example 12 watts/12 volts = 1 amp for a US example, a food mixer with a 400 watt motor on a 120 volt supply 400/120 = 3.33amps, fit a 5amp fuse
The maximum power consumption for a device operating at 30 amps is 360 watts.
"Volt" is a unit of potential difference. "Joule" is a unit of energy. There is no direct conversion from one to the other. -- If a 2-ohm resistor is connected to a 5-volt battery, then the current through the resistor is volts/ohms = 2.5 amperes. -- The power supplied by the battery and dissipated by the resistor is (volts) x (current) = 12.5 watts. -- "12.5 watts" means "12.5 joules of energy every second".
yes at the carb
The notation "2.4 kwh" is a shorthand description for 2,400 Watts of electrical power used within a time interval of one hour. The letter "k" indicates "kilo", which further indicates a multiplier of 1000. The letter "w" indicates "Watt", which is a unit of electrical power. Therefore, 2.4 kw is another way to describe 2,400 Watts. A Watt can be calculated from two other electrical quantities: Electrical current (measured in Amperes or "Amps") and electrical potential (measured in Volts). By multiplying these two quantities together (Amps and Volts), a measurement of electrical power, in Watts, can be determined. For example, the motor in a clothes dryer may operate by using 3 Amps of current and 120 Volts. In this case, the motor is said to be consuming 360 Watts of electrical power (3 X 120 = 360), or 0.360 kw or 0.360 Kilowatts (0.360 X 1000 = 360). The letter "h" indicates a unit of time, in this case "hour". If the motor in the example above continues to operate for one hour, then the motor's total consumption of power is 360 Watt hours or 0.360 Kilowatt hours (wh or kwh). Or, if instead, the motor operates for 3 hours then total consumption is 1,080 wh (360 X 3) or 1.08 kwh (0.360 X 3 = 1.08).
The notation "2.4 kwh" is a shorthand description for 2,400 Watts of electrical power used within a time interval of one hour. The letter "k" indicates "kilo", which further indicates a multiplier of 1000. The letter "w" indicates "Watt", which is a unit of electrical power. Therefore, 2.4 kw is another way to describe 2,400 Watts. A Watt can be calculated from two other electrical quantities: Electrical current (measured in Amperes or "Amps") and electrical potential (measured in Volts). By multiplying these two quantities together (Amps and Volts), a measurement of electrical power, in Watts, can be determined. For example, the motor in a clothes dryer may operate by using 3 Amps of current and 120 Volts. In this case, the motor is said to be consuming 360 Watts of electrical power (3 X 120 = 360), or 0.360 kw or 0.360 Kilowatts (0.360 X 1000 = 360). The letter "h" indicates a unit of time, in this case "hour". If the motor in the example above continues to operate for one hour, then the motor's total consumption of power is 360 Watt hours or 0.360 Kilowatt hours (wh or kwh). Or, if instead, the motor operates for 3 hours then total consumption is 1,080 wh (360 X 3) or 1.08 kwh (0.360 X 3 = 1.08).
On a 120 volt supply, up to 360 watts. On a 240 volt supply, up to 720 watts.
check your timing and vacuum advance and vacuum leaks. from there check fuel delivery system.
To convert kVA to amps, you need to also know the voltage. If we assume a standard voltage of 480V, then 300 kVA would be approximately 360 amps. This is calculated by dividing the kVA by the voltage and then converting to amps using the formula: Amps = (kVA * 1000) / (1.732 * Volts) where 1.732 is the square root of 3.
To determine if the vacuum advance on an AMC 360 is faulty, start by disconnecting the vacuum hose from the distributor and checking for any vacuum leaks or cracks in the hose. Next, use a hand-held vacuum pump to apply vacuum to the advance unit; if the diaphragm holds vacuum and the advance mechanism moves freely, it's likely functioning properly. If the diaphragm leaks or does not hold vacuum, or if there's no movement in the advance, the vacuum advance is likely bad and should be replaced. Additionally, checking for erratic ignition timing under varying engine speeds can also indicate a malfunctioning vacuum advance.