45000 / 208 /sqrt(3) = 125A per phase
this is probably called a boiler unless it has a 2000Gallon tank
To calculate the amp draw for a 3800-watt water heater at 240 volts, use the formula: Amps = Watts / Volts. Thus, the amp draw would be 3800 watts / 240 volts, which equals approximately 15.83 amps. Therefore, the water heater draws about 16 amps.
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
Watts = Amps x Volts for a resistive load like a water heater.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
To answer this question the voltage of the heater must be given. I = W/E.
To calculate the amp draw for a 3800-watt water heater at 240 volts, use the formula: Amps = Watts / Volts. Thus, the amp draw would be 3800 watts / 240 volts, which equals approximately 15.83 amps. Therefore, the water heater draws about 16 amps.
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
Watts = Amps x Volts for a resistive load like a water heater.
Watts is the amount of power the heater has and amps would be the draw- if it is a 120 volt heater than the amps would be 12.5 amps and it is instantaneous
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
To calculate the current (in amps) drawn by a 3-phase heater, you can use the formula: [ \text{Current (I)} = \frac{\text{Power (P)}}{\sqrt{3} \times \text{Voltage (V)}} ] For a 10.6 kW heater at 208 volts, the calculation would be: [ I = \frac{10,600 , \text{W}}{\sqrt{3} \times 208 , \text{V}} \approx 27.8 , \text{amps} ] Thus, the heater will draw approximately 27.8 amps.
30
The amperage draw of a hot water tank typically depends on its size and power rating. A standard electric hot water heater usually operates at either 120 or 240 volts, drawing between 10 to 30 amps. For example, a 4500-watt heater running on 240 volts would draw about 18.75 amps. Always check the manufacturer's specifications for the exact amperage.
To calculate the amperage draw, you can use the formula P = V x I, where P is the power in watts, V is the voltage in volts, and I is the current in amps. Given that the power is 1200 watts and voltage is 120 volts, you can rearrange the formula to solve for current. Therefore, I = P / V, so the amperage draw of the heater would be 10 amps.