45000 / 208 /sqrt(3) = 125A per phase
this is probably called a boiler unless it has a 2000Gallon tank
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
Watts = Amps x Volts for a resistive load like a water heater.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
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To answer this question the voltage of the heater must be given. I = W/E.
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
Watts = Amps x Volts for a resistive load like a water heater.
Watts is the amount of power the heater has and amps would be the draw- if it is a 120 volt heater than the amps would be 12.5 amps and it is instantaneous
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
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To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
To calculate the amperage draw, you can use the formula P = V x I, where P is the power in watts, V is the voltage in volts, and I is the current in amps. Given that the power is 1200 watts and voltage is 120 volts, you can rearrange the formula to solve for current. Therefore, I = P / V, so the amperage draw of the heater would be 10 amps.
A single phase 10 HP motor will draw aproximately 50 amps. A three phase 10 HP motor will draw aproximately 28 amps.
The GE water heater SE50M12AA01 is a 5500 watts or 5.5 Kilowatts water tank. The amperage on such a tank is I = W/E. Amps = Watts/Volts. Since most hot water tanks in North America use a voltage of 240, the amps will be 22.9 amps. It must be fed with a #10 conductor from a 30 amp breaker.
The formula you are looking for is I = W/E.