To calculate the amperage, use the formula: Amperes = Watts / Volts. In this case, 55 kW is 55,000 watts. So, Amperes = 55,000 watts / 460 volts ≈ 119.57 amps.
To find the amperage, you can use the formula: Watts = Volts x Amps. Rearranging it, we get Amps = Watts / Volts. Plugging in the values for 3000 Watts and 460 Volts, we get: Amps = 3000 / 460 = 6.52 amps.
The power used by the heater can be calculated using the formula: Power = Voltage x Current. In this case, the power would be 460 volts x 5 amps = 2300 watts.
It depends on the internal circuit of the machine. If it is star operated its full load current will be same as rated current. If it is Delta operated its full load per phase current will be as given below : Phase current = Line Current / 1.732
A voltage of 460 volts can be deadly if it passes through the human body. It is higher than standard household voltages, increasing the risk of severe electric shock and potential fatalities. It is important to always exercise caution and follow safety protocols when working with or near high voltage systems.
dear all, 460/600 = 2/3 =0.66... you mean operating the motor at 2/3rd the volts.... 1. you may run the motor in star connection, speed will be little less then the synchronous speed, but as long as starting torque & running torque matches the load requirements, you may operate the same on lesser volts. In fact, starting line currents will be less. 2. Use VFD drive - to keep v/f ratio same, then, you get the full load rated torque even at the 460 volts.
To find the amperage, you can use the formula: Watts = Volts x Amps. Rearranging it, we get Amps = Watts / Volts. Plugging in the values for 3000 Watts and 460 Volts, we get: Amps = 3000 / 460 = 6.52 amps.
what is the full load amps for 2.4 hp motor at 460 volts ?
The power used by the heater can be calculated using the formula: Power = Voltage x Current. In this case, the power would be 460 volts x 5 amps = 2300 watts.
750 watts per horse power20 x 750 = 15,000 watts / 220V = 68A68 amps at 220 volts
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
This depends solely on the load you might need a 15 amp service or a 1200 amp service. To find out look at the installation instructions and it will tell you what size the service supply needs to be. Watts = Amps times Volts Amps = Watts divided by Volts Volts = Amps divided by Watts Example 1500 Watt unit will pull 12.5 Amps at 120 Volts or 1500 Watt unit will pull 3.26 Amps at 460 volts or A 460 volt unit rated for 34 amps will be using 15.64 kWh or 15,640 Watts Also the higher the voltage, the lower the Amperage, however, the wattage will stay the same <<>> The question is asking about two different values. Voltage is an insulation value whereas amperage is a conductor size. The basic insulation values are 300, 600 and 1000 volts. In the question on this service, a insulation factor of 600 volts will be used for the conductors. The amperage of a service is based on the connected load that needs to be supplied. The load can be an individual load or as in a distribution panel a variety of loads. At 460 volts, the service can be either a three phase service or a single phase service. Once the load amperage has been established, the wire size for the service can be calculated. Once the wire has been sized, the breaker used to protect the wire from being overloaded will be calculated.
It depends on the internal circuit of the machine. If it is star operated its full load current will be same as rated current. If it is Delta operated its full load per phase current will be as given below : Phase current = Line Current / 1.732
depends what the source voltage isone horsepower equals to 746watts (assuming 100% efficiency)746 watts divided by voltage source equals current (amps)AnswerIn countries, such as the USA, where the horsepower is still used as a means of measuring power, it is always used to measure the output power of a motor.So, in order to determine the current drawn by the motor, you will first need to find out its input power. The input power is the output power divided by the machine's efficiency. Once you know its input power, then you can find its current by dividing the input power by the supply voltage. In practise, you will need to use a wattmeter to determine its input power.
30 HP at 480 (3 Phase) - 746 multiplied by 30 = 22380 22380 divided by 480 (3 Phase) = 46.5 46.5 divided by 1.73 = 29.5AMPS Motor speed and efficiency may change the actual result. Always refer to the name plate data
A voltage of 460 volts can be deadly if it passes through the human body. It is higher than standard household voltages, increasing the risk of severe electric shock and potential fatalities. It is important to always exercise caution and follow safety protocols when working with or near high voltage systems.
Read the specification plate on the motor to determine the amount of current that the motor uses, as well as the voltage and phase. Most likely, it will be a 3 phase motor, so you can't simply connect it to your house wiring, but without sufficient information, it is impossible to tell you all of the specifics. <<>> The code book rates the amperage of a three phase 40 HP motor by different voltages. at 200 volts - 120 amps, 230 volts - 104 amps, 460 volts - 52 amps and 575 volts - 52 amps. A breaker for a motor has to be sized to 250% of the motors full load amps. Also the wire size for a motor has to be 125% of the motor full load amps.