4000 watts on a 240 v system would be 4000/240 amps, 17 amps.
There are zero amps in a 300 watt bulb. Watts are the product of amps times volts. W = A x V. To find amperage use the equation A = W/V. If you find the voltage of the 300 watt bulb uses, divide the wattage by the voltage and it will give you the amps of a 300 watt bulb.
To find the current flowing to carry 240 watts at 120 volts, you can use the formula ( P = V \times I ), where ( P ) is power, ( V ) is voltage, and ( I ) is current. Rearranging this gives ( I = \frac{P}{V} ). Plugging in the values, ( I = \frac{240 \text{ watts}}{120 \text{ volts}} = 2 \text{ amps} ). Thus, a current of 2 amps must flow to carry 240 watts at 120 volts.
To calculate the load in amps for the circuit, first determine the total wattage of the fixtures. The four 150W incandescent fixtures contribute 600W (4 x 150W), and the six fluorescent fixtures (assuming a typical wattage of 32W each) contribute 192W (6 x 32W). Adding these together gives a total of 792W. Using the formula ( \text{Amps} = \frac{\text{Watts}}{\text{Volts}} ), the load in amps is ( \frac{792W}{120V} = 6.6A ).
1,219.2 meters.
To determine the battery's capacity in amp-hours (Ah), you multiply the current (in amps) by the time (in hours). In this case, a battery that can produce six amps for four hours has a capacity of 6 amps × 4 hours = 24 amp-hours. Therefore, the current rating of the battery is 24 Ah.
In the US at least, no, linear amps are not legal for use on CB radios. The maximum wattage permitted for AM transmission is four watts, and the maximum wattage permitted for Single Sideband is 12 watts.
There are zero amps in a 300 watt bulb. Watts are the product of amps times volts. W = A x V. To find amperage use the equation A = W/V. If you find the voltage of the 300 watt bulb uses, divide the wattage by the voltage and it will give you the amps of a 300 watt bulb.
Twenty-four thousand.
four thousand
Four hundred thousand thousand. (400,000)
24.357 is twenty-four and three hundred fifty-seven thousandths.
It is 4,000 = four thousand
16,000,000
The amps that a four gauge wire will handle will depend with the thickness of the wire. If the wire is thin, the four gauge will handle 95 amps.
To find the current flowing to carry 240 watts at 120 volts, you can use the formula ( P = V \times I ), where ( P ) is power, ( V ) is voltage, and ( I ) is current. Rearranging this gives ( I = \frac{P}{V} ). Plugging in the values, ( I = \frac{240 \text{ watts}}{120 \text{ volts}} = 2 \text{ amps} ). Thus, a current of 2 amps must flow to carry 240 watts at 120 volts.
Ninety-four thousand.
400,000 = four hundred thousand.