One amu is equal to the mass of 1/12 of a carbon-12 atom.
602x10-25 amu
6.02 X 10 23 amu
[object Object]
6.022x10^23
1.66
1 g hydrogen (H) has 6,022 140 857.10e23 atoms.
Carbon weighs 12 amu / 12 g/mol and hydrogen weighs 1 amu / 1 g/mol. Therefore, C60H122 would weigh 12*60 + 1*122 = 720 + 122 = 842 amu / 842 g/mol.
An atomic mass unit equates to 1.66053892e-24 grams.
Firstly, find the percent composition of hydrogen in the compound (ammonium nitrate). So we have: 2 x Nitrogen atom = 28.02 amu 4 x Hydrogen atoms = 4.04 amu 3 x Oxygen atoms = 48.00 amu Total of: 80.06 amu or g/mol % H = 4.04 g/mol ÷ 80.06 g/mol = 0.050462153385 = 5.05 % (sig. figs.) Then, we take the percentage of hydrogen and multiply it by the mass of the substance. 50.00 g NH4NO3 x 0.050462153385 = 2.52310766925 = 2.52 g H So, there is 2.52 g of hydrogen in 50.00 g of NH4NO3
Cadmium (Cd) has an atomic mass of 112.4 amu.3.00 g Cd x 1 mole Cd/112.4 g x 6.02x10^23 atoms/mole = answer
The equivalent is 4,69.10e24 amu.
1 g hydrogen (H) has 6,022 140 857.10e23 atoms.
1 g hydrogen (H) has 6,022 140 857.10e23 atoms.
This is misunderstood. An amu is a unit of mass,so it doesn't matter what substance you are talking about. It is much smaller than a gram.
Carbon weighs 12 amu / 12 g/mol and hydrogen weighs 1 amu / 1 g/mol. Therefore, C60H122 would weigh 12*60 + 1*122 = 720 + 122 = 842 amu / 842 g/mol.
An atomic mass unit equates to 1.66053892e-24 grams.
The equivalent is 36,53.10e-24 g.
The equivalent is 298,89.10e-24 g.
Firstly, find the percent composition of hydrogen in the compound (ammonium nitrate). So we have: 2 x Nitrogen atom = 28.02 amu 4 x Hydrogen atoms = 4.04 amu 3 x Oxygen atoms = 48.00 amu Total of: 80.06 amu or g/mol % H = 4.04 g/mol ÷ 80.06 g/mol = 0.050462153385 = 5.05 % (sig. figs.) Then, we take the percentage of hydrogen and multiply it by the mass of the substance. 50.00 g NH4NO3 x 0.050462153385 = 2.52310766925 = 2.52 g H So, there is 2.52 g of hydrogen in 50.00 g of NH4NO3
to find molar mass you add the molar mass of the carbons 3(amu)+ molar mass of the hydrogens 8(amu) to find molar mass you add the molar mass of the carbons 3(amu)+ molar mass of the hydrogens 8(amu)
Step 1. Find limiting agent (g of H2 / amu) and (g of Cl2 / amu) Cl2 is less mole so it is limiting Step 2. Find the ratio (1:2) 1H + 1Cl = 2 HCl Step 3 mole of limiting x ratio (2) x amu of HCl Source Mastering Chemistry
Gram mole is the mass of a substance which equal to molecular mass in amu. For ammonia we have one nitrogen atom and three atoms of hydrogen. So the molecular mass in amu will be 14+3 = 17 Now 17 g of ammonia would have 6.023 x 1023 molecules. ie avagadro number of molecules. Hence every 1 g will have (6.023/17) x 1023 So for 32 g it would have (32/17) x 6.023 x 1023 molecules.