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F you balance the equation below what should be the coefficient for rubidium (Rb) Rb(s) plus Cl2(g) RbCl(s)?
To balance the equation Rb(s) + Cl2(g) → RbCl(s), we need to ensure that the number of atoms for each element is the same on both sides. Since one molecule of Cl2 contains two chlorine atoms, we need two rubidium atoms to react with it. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) equal to 2.
If you balance the equation below what should be the coefficient for rubidium (Rb) Rb(s) plus Cl2(g) RbCl(s)?
To balance the equation Rb(s) + Cl2(g) → RbCl(s), you need to ensure that the number of atoms of each element is the same on both sides. Since Cl2 has two chlorine atoms, you need two rubidium chloride (RbCl) units to balance the chlorine. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) 2.
How many electrons do Rb have?
Rubidium (Rb) has a +1 ion, will have the same electron configuration as krypton (Kr) because the +1 status means it has lost an electron. The configuration is written 1s22s22p63s23p64s23d104p6.
How many valence electrons does Rb have?
1 -apex
How many valence electrons do Rb have?
Rubidium has one valence electron in the 5s orbital.
How many moles of are in 1.5 x 1024 atoms of Rb?
1.5 X 10^24 atoms Rb (1 mole Rb/6.022 X 10^23) = 2.5 moles of rubidium -------------------------------
How many atoms are in rb3po4?
There are 17 atoms in ( \text{Rb}_3\text{PO}_4 ) - 3 rubidium atoms, 1 phosphorus atom, and 4 oxygen atoms.
F you balance the equation below what should be the coefficient for rubidium (Rb) Rb(s) plus Cl2(g) RbCl(s)?
To balance the equation Rb(s) + Cl2(g) → RbCl(s), we need to ensure that the number of atoms for each element is the same on both sides. Since one molecule of Cl2 contains two chlorine atoms, we need two rubidium atoms to react with it. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) equal to 2.
What atoms forms the cation in the compound rubidium oxide?
Rubidium will form cation: Rb+
How many grams in 238 moles of arsenic?
The conversion factor you need for this problem is the atomic mass of titanium.47.9 gram titanium = 1 mole titaniumSince you want to end up in units of grams of Ti, this goes in the numerator (on top). You want to convert from moles Ti, so this goes in the denominator (on the bottom).moles Ti47.9 gram Ti = grams Ti1 moles Ti
How many protons does the element RB have?
Each atom of Rubidium (Rb) has 37 protons.
If you balance the equation below what should be the coefficient for rubidium (Rb) Rb(s) plus Cl2(g) RbCl(s)?
To balance the equation Rb(s) + Cl2(g) → RbCl(s), you need to ensure that the number of atoms of each element is the same on both sides. Since Cl2 has two chlorine atoms, you need two rubidium chloride (RbCl) units to balance the chlorine. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) 2.
What are the largest 6 atoms in the periodic table?
These elements are Cs, Rb, K, La, Ac, Po, Tl.
Rank from most to fewest valence electrons- Sb In Rb Xe?
Sb has 5 valence electrons, In has 3, Rb has 1 valence electron and Xe has 8. So in ranking, it would be, Xe, Sb, In, Rb.
What is the molar mass of Rb2Cr2O7?
The molar mass of Rb2Cr2O7 (rubidium dichromate) can be calculated by adding the atomic masses of all its constituent elements: 2 atoms of rubidium (Rb), 2 atoms of chromium (Cr), and 7 atoms of oxygen (O). The molar mass comes out to be approximately 387.87 g/mol.
How many neurons are in an atom of 82 Rb?
There are no neurons in an atom of 82 Rb. Neurons are specialized cells found in the nervous system of living organisms, while atoms of rubidium-82 (82Rb) are composed of protons, neutrons, and electrons.
How many electrons do Rb have?
Rubidium (Rb) has a +1 ion, will have the same electron configuration as krypton (Kr) because the +1 status means it has lost an electron. The configuration is written 1s22s22p63s23p64s23d104p6.
