1mole I atoms = 126.90447g
1 mole I atoms = 6.022 x 1023 atoms I
Convert grams I to moles I
85.979g I x (1mol I/126.90447g I) = 0.67751mol I
Convert moles I to atoms I
0.6775mol I x (6.022 x 1023 atoms I/1mol I) = 4.080 x 1023 atoms I
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The number of atoms is 1,50553521.10e23.
Calcium iodide (CaI2) has two iodine atoms and one calcium atom.
In iodine (I2), each iodine atom has three lone pairs of electrons. Since there are two iodine atoms in the molecule, I2 has a total of six lone pairs. However, these lone pairs are localized on each individual iodine atom and do not participate in bonding between the two atoms.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
6, one atom of Iodine and 5 atoms of Chlorine
Iodine typically exists as diatomic molecules (I2) with 2 iodine atoms per molecule. Therefore, there are 2 iodine atoms in 1 molecule of iodine.
Potassium iodide is two atoms, one of potassium and one of iodine.
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Calcium iodide has a total of 3 atoms: 1 calcium atom and 2 iodine atoms.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
After 10740 years, half of the sample would have decayed, so there would be 200 atoms left. If the original sample had 400 atoms, then there would be 200 atoms left in the sample after 10740 years.
3; 1 calcium and 2 iodine
The number of atoms is 1,50553521.10e23.
There are three elements in PbI2: lead (Pb), iodine (I), and two iodine atoms bonded to the lead atom.
There are approximately 6 x 10^22 atoms in a 12.0 gram sample of sodium.
Approx. 9.1024 atoms.