6.747 moles of lead (6.022 X 10^23/1 mole Pb)
= 4.063 X 10^24 atoms of lead
To calculate the number of atoms in 80 grams of lead, you first need to determine the number of moles of lead using its molar mass (207.2 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms. So, for lead, there are approximately 3.86 x 10^23 atoms in 80 grams.
48,177 134 32.1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
1.13x10^23
There are 1.204 x 1023 atoms in .200 mol of Pb.
To find the number of atoms in 0.23 g of lead (Pb), you first need to determine the number of moles using the molar mass of lead. Lead has a molar mass of approximately 207.2 g/mol. Then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
6.755 moles lead (6.022 X 1023/1 mole Pb) =6.755 x 6.022 X 1023 =4.068 X 1024 atoms of lead =====================
A 1 cm³ cube of lead contains approximately 2.54 x 10²² atoms. This calculation is based on the density of lead, which is about 11.34 g/cm³, and the molar mass of lead, approximately 207.2 g/mol. Using Avogadro's number (6.022 x 10²³ atoms/mol), we can determine the total number of atoms in that volume.
To calculate the number of atoms in 80 grams of lead, you first need to determine the number of moles of lead using its molar mass (207.2 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms. So, for lead, there are approximately 3.86 x 10^23 atoms in 80 grams.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
The answer is 18,061.1023 atoms.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
48,177 134 32.1023 atoms
There are 0.45 mol of BaSO4. In one mole of BaSO4, there is one sulfur atom. Therefore, there are 0.45 mol of sulfur atoms in 0.45 mol of BaSO4.
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms