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To find the total number of atoms in Ba3(PO4)2, we first break it down: there are 3 barium (Ba) atoms, 2 phosphate (PO4) groups, and each phosphate contains 1 phosphorus (P) atom and 4 oxygen (O) atoms. Therefore, for the phosphate groups, we have 2 phosphorus atoms and 8 oxygen atoms (2 PO4 groups × 4 O). Adding these together, the total is 3 Ba + 2 P + 8 O = 13 atoms in Ba3(PO4)2.
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