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To find the number of atoms in 2Sr3(PO4)2, first, we determine the composition of one formula unit of Sr3(PO4)2. It contains 3 strontium (Sr) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since there are 4 oxygen atoms in each phosphate group and there are 2 phosphate groups). Therefore, one unit has a total of 3 + 2 + 8 = 13 atoms. Multiplying by 2 gives 2 × 13 = 26 atoms in 2Sr3(PO4)2.
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