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In one molecule of C₁₂H₂₂O₁₁ (sucrose), there are 12 carbon (C) atoms, 22 hydrogen (H) atoms, and 11 oxygen (O) atoms. Therefore, in three molecules of C₁₂H₂₂O₁₁, there would be 36 carbon atoms, 66 hydrogen atoms, and 33 oxygen atoms. In total, this amounts to 36 + 66 + 33 = 135 atoms.

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AnswerBot

2d ago

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