p = 4.5 g cm-3 length = 2.68 cm Volume = (2.68 cm)3 = 19.25 cm3 mass = 19.25 x 4.5 = 86.6 g Ar = 47.9 g/mol 86.6 g = 86.6/47.9 mol = 1.81 mol Number of atoms = 1.81 x 6.02 x 1023 = 1.09 x 1024 atoms
It would depend on the type of atom. Atoms of different elements come in different sizes. We can take an average of about 1 angstrom, that is 10^-10 meters or 10^-8 cm. Using that average you would need 10^8 atoms.
To calculate the number of helium atoms needed to make a chain 1 cm long, divide the length of the chain (1 cm = 10,000 pm) by the diameter of a single helium atom (100 pm). So, 10,000 pm / 100 pm = 100 helium atoms. Therefore, 100 helium atoms placed end to end would make a chain 1 cm long.
To calculate the number of atoms in 19.3 grams of gold, you need to first determine the number of moles of gold. Then, you can use Avogadro's number (6.022 x 10^23) to find the number of atoms. Given that the sheet is only 0.00010 cm thick and the density of gold is 19.3 g/cm^3, you can determine the area of the sheet and then calculate the number of atoms.
it depends on how much water you have. but the density is 1g/cm^(3) .
There are approximately 5 x 10^22 silicon atoms in 1 cm^3 of material.
There are approximately 2.42 x 10^22 atoms in 1 cm^3 of carbon, assuming a density of 2.26 g/cm^3 and an atomic weight of 12.011 g/mol for carbon.
Approximately 100,000,000. This assumes the atoms are one Angstrom apart, which is actually a little closer than you can pack most of them; for larger atoms, half of that would be a reasonable number.
A 1 cm³ cube of lead contains approximately 2.54 x 10²² atoms. This calculation is based on the density of lead, which is about 11.34 g/cm³, and the molar mass of lead, approximately 207.2 g/mol. Using Avogadro's number (6.022 x 10²³ atoms/mol), we can determine the total number of atoms in that volume.
8.5 cm long 6 cm wide and 1,000,000 Atoms tall
p = 4.5 g cm-3 length = 2.68 cm Volume = (2.68 cm)3 = 19.25 cm3 mass = 19.25 x 4.5 = 86.6 g Ar = 47.9 g/mol 86.6 g = 86.6/47.9 mol = 1.81 mol Number of atoms = 1.81 x 6.02 x 1023 = 1.09 x 1024 atoms
It would depend on the type of atom. Atoms of different elements come in different sizes. We can take an average of about 1 angstrom, that is 10^-10 meters or 10^-8 cm. Using that average you would need 10^8 atoms.
To find the number of atoms per cm^3 from density, you first need to know the atomic mass of the material. Calculate the molar volume (cm^3/mol) using the molar mass of the material. Then convert to cm^3/atom by dividing by Avogadro's number (6.022 x 10^23). Finally, divide the material's density by the molar volume to get the number of atoms per cm^3.
To calculate the number of helium atoms needed to make a chain 1 cm long, divide the length of the chain (1 cm = 10,000 pm) by the diameter of a single helium atom (100 pm). So, 10,000 pm / 100 pm = 100 helium atoms. Therefore, 100 helium atoms placed end to end would make a chain 1 cm long.
To calculate the number of atoms in 19.3 grams of gold, you need to first determine the number of moles of gold. Then, you can use Avogadro's number (6.022 x 10^23) to find the number of atoms. Given that the sheet is only 0.00010 cm thick and the density of gold is 19.3 g/cm^3, you can determine the area of the sheet and then calculate the number of atoms.
How many inches is 38 cm
If we assume that the distance between each atom is about 1 Angstrom (1×10−10m) apart, we can calculate that there are approximately 100,000,000 atoms in a 1cm line, give or take depending on the size of the atom.