To cover 2000 square feet with a few inches of straw, you typically need about 2 to 3 bales of straw per 100 square feet for a depth of 2-3 inches. Therefore, for 2000 square feet, you would require approximately 40 to 60 bales of straw, depending on the thickness of the coverage and the density of the straw. It's essential to consider the specific type and packing of the straw bales, as they can vary in size and weight.
If those are inches, the area is 143 square inches.
The practical unit of area for the front cover of a book is typically measured in square inches or square centimeters. This measurement helps to determine the dimensions of the cover, which commonly includes height and width. For example, a standard novel might have a cover area of about 6 inches by 9 inches, resulting in an area of 54 square inches.
Knowing how many square yards in feet will cover when working with depths up to six inches, in important to know, especially in construction. There will be 54 square feet when you have a depth of six inches.
As a rule of thumb, 0.112 tons of asphalt (2" thick) will cover 1 square yard or 9 square feet. Thus 1 tone of asphalt (2" thick) will cover 8.93 square yards or 80.36 square feet. ------------------------------- Another (possibly more accurate) way of doing this is to use standards 1 ton [long, UK] = 2240 pounds Density of compacted Asphalt = 147 pounds per cubic foot (1728 cubic inches) 12 inches times 12 inches times 2 inches = 288 cubic inches Thus the weight of 288 cubic inches of compacted asphalt will be (288/1728)* 147 = 24.5 pounds. Therefore a tone of asphalt will cover 2240/24.5 = 91.43 square feet to a depth of 2 inches.
Part 1: There are 36 inches in a yard. So a square yard is 36 x 36 square inches = 1296. Part 2: Each square yard is 36 X 36 inches [length and width] Having multipied this ... then seeing that you want 3 of these square yards, you multiply your first answer by 3. So, 36 X 36 = 1296... Then for 3 square yards: 1296 X 3 = 3,888 square inches.
I would guess about 70-80 bales
Assuming a standard bale size of 14 inches high by 18 inches wide by 36 inches long, and assuming the bales are only one layer deep, 90 bales would cover a little over 400 square feet.
It will depend on the size of the bale. Bales come in different sizes, but most will cover somewhere between 20 square feet to 120 square feet at about 2.5 to 3 inches deep. Ask that question when purchasing your bales since the size does vary considerably and some bales are machined compressed and some are hand compressed. For that reason, just looking at a bale and comparing the sizes does not always tell you how many square feet a particular bale will cover.
An acre is 43,560 square feet. Most small square bales would lightly cover at least 2x10 ft, but more likely 2x15 ft . Therefore; 43,560 divided by 30 (if each square bale covers 30 sq/ft as an average) = 1,452 square bales. If the bales are larger (round bales), obviously fewer bales would be required. Large round bales would likely provide at least 10X the coverage so likely in the range of 145 round bales
If those are inches, the area is 143 square inches.
Each tile covers 81 square inches. You have 1,296 square inches to cover. It will take 16 tiles to cover that area.
It depends how thick the gravel is being laid - at 4 inches thick, a cubic yard will cover 81 square feet.
6.14 x 2.61 = 16.0254 square inches = 0.00000000399188978 square miles x 1000000000 = 3.99188978 square miles. Call it 4 square miles.
1.174 square feet.
144
1 (cubic yard) = 46 656 cubic inchesIf the depth is 2 inches then the area it will cover is 46656/2 square inches = 23,328 square inches. Convert 23,328 square inches to square yards23 328 (square inches) = 18 square yards
80 inches squared to just cover it