There are 3 billion base pairs per cell in a human diploid.
There are 7 nitrogen atoms in the base pair A-T.
GC base pairs are more stable than AT base pairs because they have three hydrogen bonds holding them together, while AT base pairs have only two hydrogen bonds. This extra bond in GC pairs makes them stronger and more difficult to break apart.
Uracil is the base in RNA that pairs with adenine.
Thymine base pairs with adenine in DNA, forming a T-A base pair. Uracil base pairs with adenine in RNA, forming a U-A base pair.
According to Hong et al (2006), the average size of an intron is 3479 base pairs. However, the average is skewed by some very large introns. A better picture comes from the median size, which is 1334 base pairs. Reference: Hong X, Scofield DG, Lynch M (2006) Intron size, abundance, and distribution within untranslated regions of genes. Mol. Biol. Evol. 23:2392-404
four base pairs
there are five base pairs in klinefelter syndrome
The human genome consists of about 3 billion base pairs.
There are three base pairs in each amino acid. If you have 1500 base pairs you would have 500 amino acids.
There are approximately 3 billion base pairs in the human genome.
A gene typically contains thousands to millions of base pairs.
There are 3 billion base pairs per cell in a human diploid.
The yeast Saccharomyces cerevisiae has a genome size of approximately 12.1 million base pairs.
The number of base pairs formed by 8 DNA nucleotides is 8.
mRNA that includes introns due to errors in mRNA processing will generate dysfunctional or truncated proteins. If the intron introduces a stop codon in the middle of the sequence a truncated protein will be produced. If the intron does not introduce a stop codon the end result is still going to be a protein with many unnecessary amino acids that will most likely interfere with folding and stop it from becoming functional.
If there are 40 pairs containing base C, the remaining pairs must contain the complementary base, G. Since each base pair must contain one A and one T (complementary to each other), the number of pairs containing base A would be the same as the number containing base T. Therefore, there would be 60 pairs containing base A.