The formula unit for the most common form of calcium phosphate is Ca3(PO4)2. Therefore each formula unit, the ionically bonded counterpart of a mole for covalently bonded compounds, contains three calcium ions. The number of calcium ions in 8.0 "moles" of calcium phosphate is 3 [exact] X 8.0 X Avogadro's Number or 1.45 X 1025 atoms, where the depressed last digit of 1.45 indicates that this digit may not be significant. (The significant-digits-limiting datum is 8.0 moles.)
A mole of calcium has 6.022 X 1023 calcium ions.
Calcium iodide is an ionic compound composed of one calcium ion (Ca2+) and two iodide ions (I-). Therefore, there are a total of 3 ions present in calcium iodide.
three sodium ions
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The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
The individual ions for calcium fluoride have the formulas Ca+2 and F-1 respectively. That means that in any sample of calcium fluoride, there must be twice as many of the fluoride ions.
There are two types of ions in this compound, calcium ions and hydroxyl ions. The number of ions present in a sample can be calculated if the mass of the sample is known.
A mole of calcium has 6.022 X 1023 calcium ions.
Two potassium ions are needed to bond with one phosphate ion. Potassium has a +1 charge while phosphate has a -3 charge, so it takes two potassium ions (each with a +1 charge) to balance the charge of one phosphate ion.
Calcium iodide is an ionic compound composed of one calcium ion (Ca2+) and two iodide ions (I-). Therefore, there are a total of 3 ions present in calcium iodide.
three sodium ions
Two potassium ions are needed to bond with one phosphate ion to form a stable ionic compound. The potassium ions have a +1 charge and the phosphate ion has a -3 charge, requiring three +1 charges to balance the -3 charge of the phosphate ion.
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The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
There are approximately (1.20 \times 10^{24}) calcium carbonate ions in 50g of CaCO3.
Calcium has a chrage of +2 or two positive charges