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Sulphur can exists in several oxidation states.

The oxidation state is the number of electrons in the outer energy shell of electrons, involved in bonding.

So for

Sulphuric Acid (H2SO4) sulphur is in oxid'n state '+6'. It makes two double bonds with two oxygen atoms, ; 4 bonds. It then makes a further two single bonds with the remaining two oxygen atoms, 2 bonds. Hence 4 + 2 = 6 bonds.

The two singly bonded oxygen atoms then combine with the two hydorgen atoms by single bonds(Not involving the sulphur).

Sulphurious Acid (H2SO3) sulphur is in oxid'n state '+4'. It makes one double bonds with one oxygen atom, ; 2 bonds. It then makes a further two single bonds with the remaining two oxygen atoms, 2 bonds. Hence 2 + 2 = 4 bonds.

The two singly bonded oxygen atoms then combine with the two hydorgen atoms by single bonds(Not involving the sulphur).

Atomic sulphur is in oxidation state zero'0' no bonds.

Hydrogen sulphide is in oxidation state '-2' ; Note the minus sign, This is because the electrons are 'donated' in the opposite direction, to the above molecules.

NB Sulphur can also form an oxidation state ( makes two ) '2'

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lenpollock

Lvl 17
1w ago

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