A centimetre is a unit of distance. A litre is a unit of capacity. The two units are therefore incompatible.
92.4 grams
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
2.6 cm
there are 7.62 cm. in one in.
30 in = 76.2 cm
The answer is.........................................................................................................................................2L
P=2(w)+2(l) 52=2(12)+2(l) 52=24+2l 52-24=2l 28=2l 14=l The length is 14 cm.
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
b=l-3 P=2l+b 36=2l+b Sub b=l-3 into 36=2l+b 36=2l+b 36=2l+(l-3) 36=2l+l-3 39=3l l=13 cm Sub l=13 into b=l-3. b=l-3 b=13-3 b=10 cm Therefore, the length of each of the two equal sides is 13 cm and the base is qual to 10 cm.
36 cm is the perimeter of the rectangle. Since it is the perimeter, there will be two long sides and two short sides. , making the four sides. This can be algebraically expressed as P = 2(l + s) P = 2l + 2s Substituting P = 36 sm s = 4 cm ( assumed). 36 cm = 2l + 2(4cm) 36 cm = 2l + 8 cm 2l = 36 cm - 8cm ( Note the change of sign , when 'crossing the '=' sign 2l = 28 cm Divide both sides by '2' l = 14 cm ( is the length).
The box would be about 2115 cubic cm.
There are 2000 ml in 2L. And eat a pb and jelly sandwich
Perimeter of a rectangle = 2 x length + 2 x width. 52 = 2l + 2 x 12 = 2l + 24 (Where l is the length) 2l = 52 - 24 = 28 length = 28/2 = 14 cm
p=2L+2W p=2(150)+2(15) p=300+30 p=330
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
Suppose the length is L cmThen the width is 2L - 2 cmTherefore, the area is L*W = L*(2L - 2) = 2L^2 - 2L sq cm.Then 2L^2 - 2L = 161or 2L^2 - 2L - 161 = 0therefore L = [1+sqrt(323)]/2 [the other root of the quadratic equation is negative and so cannot be a length].and then W = sqrt(323) - 1By Pythagoras,L^2 = 1/4 + 1/4*323 + sqrt(323)/4 = 81 + sqrt(323)/2W^2 = 323 + 1 - 2*sqrt(323) = 324 - 2*sqrt(323)and then D^2 = L^2 + W^2 = 405 - 3/2*sqrt(323) = 378.0417 approxand so D = 19.4433 cm, approx.
There are 2000ml in 2l