There are 7 different letters, each to represent each shell. They are: 1. K 2. L 3. M 4. N 5. O 6. P 7. Q
P and f only
Maximum number of electrons = 2n2, where n is the number of shell (n = 1 for K, 2 for L, 3 for M, and so on) K shell has 2 electrons maximum L shell has 8 electrons maximum M shell has 18 electrons maximum N shell has 32 electrons maximum O shell has 50 electrons maximum P shell has 72 electrons maximum
Mostly they are s or p electron sub-orbitals in the same (outer) shell. In the transition metals sometimes one electron from a higher d orbital gets involved ( e.g. to reach the oxidation states Fe2+ and Fe3+).
Looking at the electron configuration of carbon (at. no. 6) you have 1s2 2s2 2p2. In the 2 p subshell, you have 1 electron in the 2px orbital, and 1 electron in the 2py orbital and no electrons in the 2pz orbital. So, the answer is that there are TWO half filled orbitals in the carbon atom. This is the case BEFORE hybridization. After hybridization, there are FOUR half filled orbitals which are called sp3 hybrids.
l=1
1 electron. It is Group I of the P-table hence has one "spare" electron
There are 7 different letters, each to represent each shell. They are: 1. K 2. L 3. M 4. N 5. O 6. P 7. Q
P and f only
The second electron shell can hold a maximum of 8 electrons. This shell has 2 sublevels (s and p) which can each hold up to 4 electrons.
Maximum number of electrons = 2n2, where n is the number of shell (n = 1 for K, 2 for L, 3 for M, and so on) K shell has 2 electrons maximum L shell has 8 electrons maximum M shell has 18 electrons maximum N shell has 32 electrons maximum O shell has 50 electrons maximum P shell has 72 electrons maximum
The azimuthal quantum number (l) is also known as the sub-shell quantum number. It represents the sub-shell of an electron within a given energy level. The value of l determines the shape of the orbital (s, p, d, f).
Halogens have 5 electrons in their outermost p shell in their electrically balanced state. The p shell has 3 orbitals in each energy level. Halogens have 2 filled orbitals each with 2 electrons in them and one orbital with only one electron in it. In order to obtain the stable noble gas electron configuration, halogens gain one electron to completely fill the p shell on the outermost energy level. This gives halogens a charge of -1.
1s2, 2s2, 2p6, 3s2, 3p3 The prefix number is the energy shell number. No.1 being the inner most shell 's' or 'p' is the character of the shell. The suffix number is the number of electrons in that sub-shell.
The three in that sequence lets an observer know how many electrons are filled for that particular shell. In this case, the 2p shell has 3 out of 6 possible spaces filled.
The answer is 4s, because it is in the 4rth period of the Periodic Table of Elements =]
Phosphorus (P) has 5 electrons in its outer shell. In PCl5, phosphorus is surrounded by 5 chlorine atoms, each contributing 1 electron to form a covalent bond with phosphorus. Therefore, in the compound PCl5, phosphorus has a total of 10 electrons in its outer shell.