All right Cesium is an Alkali Metal so it belongs to the first column of the Periodic Table. Every element in that column has a charge of 1+ as a cation. So to answer your question, a single Cesium atom loses 1 electron when it becomes a cation. The cation looks like this:
Cs = 55 Electrons
Cs^+ = 54 Electrons
As you can see it only loses one :)
Cesium tends to lose electrons rather than gain them. As an alkali metal, cesium typically forms a +1 cation by losing its single valence electron to achieve a stable electron configuration.
The gain and/or lose of electrons.
A Fluorine atom has an atomic number of 9. Draw out the electron shell diagram for Fluorine. Is a Fluorine atom more likely to gain, lose or share electrons to fill its valence shell?
The term isotope is used to indicate the different varieties of a single element, based upon variations in the number of neutrons in the nucleus. Every atom can be described as an isotope if we specify the number of neutrons. And every atom can lose electrons (a process officially called ionization). There is no relation between the number of neutrons and the loss of electrons.
The kind of atom that likes to be oxidized.
It all has to due with ionization energy. Ionization energy is the energy required to remove an electron from an atom to make it an ion. Cesium has a lower ionization energy than Lithium, so it is easier to remove electrons, and thus lose electrons, from a Cesium atom than a Lithium atom.
Cesium tends to lose electrons rather than gain them. As an alkali metal, cesium typically forms a +1 cation by losing its single valence electron to achieve a stable electron configuration.
Cesium typically loses one electron to form a Cs+ cation because it has one valence electron in its outermost electron shell.
When cesium forms an ion, it loses 1 electron to form the Cs+ cation. This is very easy for cesium to do because of its very low electronegativity, which is a measure of the attraction between the nucleus and the electrons.
An atom can lose electrons to other atoms during a chemical reaction. This process results in the atom becoming positively charged, forming an ion.
The contact with an atom having a high affinity for electrons.
This is a chemical element. You can find the how many electron in a single atom by using a periodic table.
This is a chemical element. You can find the how many electron in a single atom by using a periodic table.
With metals, as atomic radius decreases, the element becomes less reactive. A smaller atom means its valence electrons are closer to the nucleus, and the nucleus (with its positive charge) holds them tighter. A metal atom with a large atomic radius will be more reactive, because its valence electrons are farther from the nucleus, and less subject to the nucleus' effective nuclear charge. For example, considering the elements sodium and cesium, cesium is the more reactive of the two, because cesium is a larger atom, and its valence electrons are farther away, and thus easier to lose. (review "ionization energy.")
The gain and/or lose of electrons.
A hydrogen atom can lose its only electron in an ionic bond. The atom would have no electrons. Actually the correct answer is No.
Beryllium tends to lose two electrons to form a 2+ cation.