according to the valency
Two electrons can occupy the 2s subshell, and 8 electrons can occupy the 3d subshell.
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In an atom with seven electrons, such as nitrogen (atomic number 7), the electron configuration is 1s² 2s² 2p³. Of these seven electrons, three occupy the P orbitals (2p³), while the other four fill the 1s and 2s orbitals. Therefore, in this case, three of the seven electrons occupy P orbitals.
No, according to the Pauli exclusion principle, no two electrons can have the same set of quantum numbers in an atom. This means that two electrons cannot occupy the same space orbital if they have the same spin.
Electrons with the smallest amount of energy would occupy the principal quantum energy level of n = 1. This is the lowest energy level, closest to the nucleus of an atom, where electrons are most stable and have the least energy. In this level, there can be a maximum of two electrons, which occupy the 1s orbital.
Two electrons can occupy the 2s subshell, and 8 electrons can occupy the 3d subshell.
the rule is 2n² so there are 2*4²= 32 electrons in the fourth orbital
The electrons in beryllium occupy a total of four orbitals. Beryllium has 4 electrons, which fill the 1s, 2s, and 2p orbitals.
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The number of electrons that can occupy each shell in an atom is determined by the formula 2n2, where n is the shell number.
Calcium's outermost electrons occupy the 4s orbital.
Only 2 electrons can reside in the innermost shell.
yes they do :D
There are a total of six electrons that occupy the p orbital of a neutral silicon atom. The p sublevel can hold a maximum of six electrons, with each p orbital accommodating two electrons with opposite spins.
there is a maximum of 6 electrons in the 'p'sublevel
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In an atom with seven electrons, such as nitrogen (atomic number 7), the electron configuration is 1s² 2s² 2p³. Of these seven electrons, three occupy the P orbitals (2p³), while the other four fill the 1s and 2s orbitals. Therefore, in this case, three of the seven electrons occupy P orbitals.