according to the valency
Two electrons can occupy the 2s subshell, and 8 electrons can occupy the 3d subshell.
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No, according to the Pauli exclusion principle, no two electrons can have the same set of quantum numbers in an atom. This means that two electrons cannot occupy the same space orbital if they have the same spin.
If by occupy, you mean what space do they occupy since they are subatomic they can fit in anything. However we don't know if they can go inside black hole but since they are infinitely dense it seems unlikely.
26 sigma 7 pi
Two electrons can occupy the 2s subshell, and 8 electrons can occupy the 3d subshell.
the rule is 2n² so there are 2*4²= 32 electrons in the fourth orbital
The electrons in beryllium occupy a total of four orbitals. Beryllium has 4 electrons, which fill the 1s, 2s, and 2p orbitals.
8
The number of electrons that can occupy each shell in an atom is determined by the formula 2n2, where n is the shell number.
Calcium's outermost electrons occupy the 4s orbital.
Only 2 electrons can reside in the innermost shell.
yes they do :D
there is a maximum of 6 electrons in the 'p'sublevel
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There are a total of six electrons that occupy the p orbital of a neutral silicon atom. The p sublevel can hold a maximum of six electrons, with each p orbital accommodating two electrons with opposite spins.
17. The electronic configuration of bromine is 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 4p5