The main rod bolts on a 1995 International DT466 typically require about 115-125 foot-pounds of torque. It is important to consult the manufacturer's specifications or a service manual for the exact torque value for your specific engine.
11 Nm is equivalent to approximately 8.1 foot-pounds of torque.
Assuming the question refers to torque, then 1 ft-lb = 12 in-lbs. If you have a torque wrench reading inch-pounds, divide by 12 to get foot pounds. Conversely, multiply foot pounds by 12 to get inch pounds. If you want to get a little more technical, then read on. Torque quantifies force applied in a twisting action, such as tightening a bolt with a wrench. The longer the lever arm (distance the force is applied from the point of rotation) the greater the torque. This assumes the force is applied in a direction perpendicular to the lever arm, which is the normal case in practice. Formally, the definition of torque is force multiplied by distance, or force acting perpendicular to the lever arm multiplied by the length of the lever arm. If you are doing something like using a torque wrench on a car, you steady the connection of the wrench to the bolt or nut to make sure the force you are applying is perpendicular to the axis define by the length of the bolt. Then the reading on the torque wrench is an accurate measure of the torque applied to the nut or bolt.
Convertng psi to ft-pounds can't be done. Its like apples to oranges, both are fruit but, they just ain't the same. 100 pounds per square inch refers to a measure of pressure, like the amount of air in your car tires or the force of the water from the tap: where foot pounds of torque is a measure of force required to rotate an object, that is, how hard it is to tighten or loosen the top on a mayonaise jar or to loosen/tighten the lug nut on a wheel. they are not proportionally related even though they both involve work/force.
There isn't a direct conversion between horsepower and torque in foot-pounds. Horsepower is a measure of power, while torque measures rotational force. Horsepower can be calculated using a formula that includes torque and engine speed.
The question was going along so nicely there, until it got to the very end, and thenshot itself in the foot with "foot pounds"."Foot pounds" is a torque, not a force.-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes175 pounds of force at the surface of the 8-inch cylinder, because the mechanicaladvantage of the crank/cylinder arrangement is 28/8 = 3.5 .-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.What a difference a unit makes !
600 foot pounds
300
90 inch - pounds (torque) = 90 / 12 = 7.5 foot pounds (torque)
Torque settings on 1300 Toyota Tazz are torque to 59 foot-pounds, loosen one full-turn. Then, torque 37 foot-pounds and 68 foot-pounds. Torque sequence is 6, 4, 2, 8,7, 3, 1, 5.
According to the Autozone website : For a 1995 Ford Windstar , 3.8 L V6 engine : The spark plug tightening torque is ( 7 to 15 foot pounds )
11 Nm is equivalent to approximately 8.1 foot-pounds of torque.
The torque setting for the pressure plate on the clutch for an s10 2.2 is 33 foot pounds. The torque for the 4.3 is 29 foot pounds.
18 foot/pounds 18 foot/pounds
The unit "nm" stands for Newton meters and is a metric unit for torque. To convert 65 Nm to foot-pounds, you can use the conversion factor 1 Nm = 0.737562 foot-pounds. Thus, 65 Nm is approximately 47.8818 foot-pounds.
100 foot pounds100 foot pounds
390
20 foot pounds