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How many formla units are present in 85.6g of AgNO3?

Anonymous

∙ 10y ago

Updated: 12/23/2022

The molar mass of silver nitrate is 169,87 g: approx. two formula units.

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∙ 10y ago

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Related Questions

How many moles of aluminum are present in 856g of aluminum sample?

To determine the number of moles of aluminum present in 856g, you need to divide the mass by the molar mass of aluminum. The molar mass of aluminum is approximately 26.98 g/mol. So, 856g ÷ 26.98 g/mol ≈ 31.7 moles of aluminum are present in 856g.

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