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How many different kinds gametes will an individual with genotype AAbb produce?

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What two types of gametes could result from AABb allele combination?

The two types of gametes that could result from the AABb allele combination are AB and Ab. This is because during meiosis, homologous chromosomes separate and randomly assort, leading to different combinations of alleles in gametes.


What will the percentage of a b gametes produced by Aa Bb parent?

The percentage of AB gametes produced by an AaBb parent is 25%. This is because during meiosis, the two alleles segregate independently, resulting in equal proportions of gametes with different combinations of alleles (AB, Ab, aB, ab). By calculating the possible combinations, we see that only 25% will be AB gametes.


What possible gametes can be produced from the f2 generation?

In the F2 generation, the possible gametes produced would be the result of the random assortment of alleles from the parents. Each parent can produce two types of gametes based on their genotype. For example, if the parents are AaBb and AaBb, the possible gametes would be AB, Ab, aB, and ab.


Where did the ratio 9331 come from include what each of these four numbers mean?

The 9/3/3/1 ration is the ratio of phenotypes that are the result of a dihybrid cross. Consider two genes, A and B, that reside on different chromosomes (so that they independently assort). Assume each gene has two alleles. For A, A is dominant and a is recessive, while for the B gene, B is dominant and b is recessive. Now consider a cross between two individuals that are heterozygous for both genes (this is called a dihybrid cross): AaBb X AaBb There are only 4 possible gametes that each individual can produce (in equal proportion): AB Ab aB ab So if we cross the two we get 16 combinations. This will result in 9 possible genotypes: AABB AABb AAbb AaBB AaBb Aabb aaBB aaBb aabb However, there are only 4 possible phenotypes (with proportion in parentheses): Dominant A and B (9/16) (AABB, AABb, AaBB, AaBb) Dominant A, Recessive B (3/16) (AAbb, Aabb) Recessive A, Dominant B (3/16) (aaBB, aaBb) Recessive A, Recessive B (1/16) (aabb)


What are the possible genotypes of the offspring from the cross ABOVE?

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What are all the possible gametes of an individual with the genotype Aabb?

Ab and ab There would be about a 50/50 ratio of each.


What is the phenotype of all four offspring's?

Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb


How many different phenotypes can be produced from intercrossing parents of genotype AaB1B2?

Four different phenotypes can be produced: AABB, AABb, AaBB, and AaBb. This is the result of different combinations of alleles from each parent in the offspring.


When was AABB created?

AABB was created in 1947.


What are the possible gametes for AAA AAA?

A gamete is haploid (1N) so 'Aa' & 'AA' are diploid and during cell division (mitosis) gametes are formed and then 2 gametes merge together to make a diploid (think of sperm and egg, each is haploid or 1N, when fertilization occurs the egg and sperm form 1 cell that is 2N or diploid). So the possible gametes for 'Aa' would be 'A' & 'a' while for 'AA' the only gametes possible are 'A' If the question is asking what the possible gametes are for 'AaBB' the haploid (gamete) can be 'AB' or 'aB'


How many types of gametes will each parent produce in problem number 1 and problem number 2?

To determine the number of types of gametes each parent produces, you can use the formula ( 2^n ), where ( n ) is the number of heterozygous gene pairs. In problem number 1, if both parents are heterozygous for one trait (Aa), each will produce 2 types of gametes (A and a). In problem number 2, if each parent is heterozygous for two traits (AaBb), they will produce 4 types of gametes (AB, Ab, aB, ab).