How many gold atoms are in 45.0 grams of gold?

Answer 1

To find the number of gold atoms in 45.0 grams of gold, first determine the molar mass of gold (Au), which is approximately 197 g/mol. Next, calculate the number of moles in 45.0 grams by dividing the mass by the molar mass: ( \frac{45.0 \text{ g}}{197 \text{ g/mol}} \approx 0.228 \text{ mol} ). Finally, multiply the number of moles by Avogadro's number ((6.022 \times 10^{23} \text{ atoms/mol})): ( 0.228 \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 1.37 \times 10^{23} \text{ atoms} ). Thus, there are approximately (1.37 \times 10^{23}) gold atoms in 45.0 grams of gold.