This mass is 325,19 g.
The molar mass of silver is approximately 107.87 g/mol. Therefore, the mass of 2.6 moles of silver would be 2.6 moles x 107.87 g/mol = 280.3 grams.
9.87670935 ounces
Approximately 4.50 grams of NaOH are required to prepare 200 mL of a 0.450 M solution. This can be calculated using the formula: moles = Molarity x Volume (in L), and then converting moles to grams using the molar mass of NaOH.
This number is 12,044 280 171 4.10e23.
1000/280 = 100/28 = 25/7 = 3.5714 grams per cubic centimeter
280 ml of water is 280 grams
1000 grams = 1 kilogram so 280 grams = 280/1000 kg = 0.28 kg.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
280
280mg is 0.28 grams (divide mg by 1,000 to get grams).
280
The molar mass of silver is approximately 107.87 g/mol. Therefore, the mass of 2.6 moles of silver would be 2.6 moles x 107.87 g/mol = 280.3 grams.
Answer: 280 g = 0.617294 lb
9.87670935 ounces
To find the molarity, first convert the mass of sulfuric acid to moles by dividing by its molar mass (98.08 g/mol). Then, calculate the molarity by dividing the moles of sulfuric acid by the volume of the solution in liters (280 mL = 0.28 L). Molarity = moles of solute / liters of solution.
1 ounce = 28.3495 gmRounded to two decimal places,280 grams = 280/28.3495 ounce = 9.88 ounces.
28 grams in an oz Source: Drug dealer