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How many moles are equal to 417.2 g of FeCrO4?
417.2 grams FeCrO4 (1 mole FeCrO4/171.85 grams) = 2.428 moles iron (II) chromate =========================( also known as ferrous chromate )
What is the weight of 1 mole of BASO4?
The molar mass of BaSO4 (barium sulfate) is 233.38 g/mol. Therefore, the weight of 1 mole of BaSO4 is 233.38 grams.
How many Bg atoms in the original sample would be expected to have the same mass as the calculated atomic mass of the element?
To determine how many barium (Ba) atoms would have the same mass as the calculated atomic mass of the element, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The atomic mass of barium is about 137.33 amu, meaning one mole of barium atoms weighs approximately 137.33 grams. Therefore, to find the number of atoms that would have a mass equal to the atomic mass of barium (in grams), you would convert 137.33 grams to moles, which would result in approximately (1) mole or (6.022 \times 10^{23}) barium atoms.
Atomic weight of barium?
Molecular weight for Barium is 137.33 amu.
How many grams of barium sulfate can be produced from 20.8 g of barium chloride?
To determine the grams of barium sulfate produced from 20.8 g of barium chloride, we first need to consider the balanced chemical reaction between barium chloride (BaCl₂) and sodium sulfate (Na₂SO₄) to produce barium sulfate (BaSO₄) and sodium chloride (NaCl). The molar mass of barium chloride is approximately 137.33 g/mol (for Ba) + 2 × 35.45 g/mol (for Cl) = 137.33 + 70.90 = 208.23 g/mol. The molar mass of barium sulfate is about 233.39 g/mol. Using stoichiometry: Calculate moles of BaCl₂: ( \text{moles} = \frac{20.8 , \text{g}}{208.23 , \text{g/mol}} \approx 0.100 , \text{mol} ). Since the reaction produces 1 mole of BaSO₄ for every mole of BaCl₂, 0.100 moles of BaCl₂ will produce 0.100 moles of BaSO₄. Convert moles of BaSO₄ to grams: ( 0.100 , \text{mol} \times 233.39 , \text{g/mol} \approx 23.34 , \text{g} ). Thus, approximately 23.34 grams of barium sulfate can be produced from 20.8 grams of barium chloride.
How many moles are equal to 417.2 g of FeCrO4?
417.2 grams FeCrO4 (1 mole FeCrO4/171.85 grams) = 2.428 moles iron (II) chromate =========================( also known as ferrous chromate )
How many moles of barium are present in a sample having a mass of 22.3 grams?
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
What is the weight of 1 mole of BASO4?
The molar mass of BaSO4 (barium sulfate) is 233.38 g/mol. Therefore, the weight of 1 mole of BaSO4 is 233.38 grams.
How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
How many Bg atoms in the original sample would be expected to have the same mass as the calculated atomic mass of the element?
To determine how many barium (Ba) atoms would have the same mass as the calculated atomic mass of the element, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The atomic mass of barium is about 137.33 amu, meaning one mole of barium atoms weighs approximately 137.33 grams. Therefore, to find the number of atoms that would have a mass equal to the atomic mass of barium (in grams), you would convert 137.33 grams to moles, which would result in approximately (1) mole or (6.022 \times 10^{23}) barium atoms.
Atomic weight of barium?
Molecular weight for Barium is 137.33 amu.
How many grams are in a mole of he?
4.003 grams
How many grams are in one mole of C5H12?
The molar mass of C5H12 is 72 grams/mole.
What is the mass for 0.92 mol aluminum chromate?
To find the mass of 0.92 mol of aluminum chromate (Al2(CrO4)3), you need to calculate the molar mass of aluminum chromate. The molar mass is calculated by adding the atomic masses of all the atoms in the chemical formula. The molar mass of aluminum chromate is approximately 469.32 g/mol. Therefore, the mass of 0.92 mol of aluminum chromate is approximately 431.42 grams.
How many grams of pseudoephedrine are in one mole?
The answer is 165,23 grams.
What is the mass of 3 moles of barium?
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
How many molecule in 25 grams of NH3?
25 grams / (17 grams/mole) x 6.022x1023 molecules/mole = 8.9x1023 molecules
