The mass of copper is 240 g.
Use the following formula:
q = m x c x DeltaT,
where:
q is energy, m is mass, c is specific heat capacity, and DeltaT is the change in temperature.
DeltaT = Tfinal-Tinitital
Known
q = 1200 cal
cCu = 0.0923 cal/g.oC
Tinitial = 20oC
Tfinal = 75oC
DeltaT = 75oC - 20oC = 55oC
Unknown
mass of copper
Solution
Rearrange the equation q = m x c x DeltaT to isolate m. Plug in the known values and solve.
m = q/(c x DeltaT)
m = 1200/(0.0923 x 55) = 240 g (rounded to two significant figures)
I don't think you actually put calories into the water. You would dissipate thermal energy that could be measured in kCal or calories to heat the water. You may be thinking of the stored thermal energy from the heated water.
They could, since magnesium is more reactive than copper, and could displace it to form magnesium nitrate.
No. Ions do not precipitate on their own. Since zinc is more reactive that copper it will replace copper. So placing zinc in a solution of a copper salt will cause elemental copper to precipitate.
Wires can get extremely hot as the current increases and the wire size decreases. An incandescent light bulb is basically a heated wire and you don't want to touch a high wattage light bulb. The temperature can get hot enough to melt copper for example if you have a sufficient source or current. Since copper melts at about 1984 degrees F, you could say under some circumstances this temperature is achieved.
In theory it could insulate the copper slightly and if the copper warmed up enough it could cause slight changes in current. If we are not talking about driving the wire to extreme loads, then no.
Carbonate by itself is an ion that does not contain copper and therefore could not produce copper if heated. However, because carbonate is a negatively charged ion, no substantial number of carbonate ions can exist stably except in association with an equal number of positively charged cations to neutralize the electrical charge of the carbonate ions. If these cations are cations of copper, then copper oxide can be produced by heating the copper carbonate salt.
Depth of the cut into the skin depends on the pressure applied and sharpness of the blade.If the knife is heated to red hot.Logically speaking one could assume it would cut less deep.As it could cauterize the cut as it enters causing more friction as it enters the wound.
Yes, hot water or boiling water will kill or damage plant tissue and could result in death, even if this is applied to the soil. Once the boiled (or heated) water has cooled it can be used to water the plants with no side effects
I don't think you actually put calories into the water. You would dissipate thermal energy that could be measured in kCal or calories to heat the water. You may be thinking of the stored thermal energy from the heated water.
Low calories could be good if you are on a diet or watching what you are eating.
In the normal conditions, it is not possible as iron is more reactive than copper. However, it is possible in an an electrolytic cell where an opposite electric potential is applied opposite to the normal potential so that the reaction could take in the opposite direction. In this case copper would be able to replace iron from iron sulphate.
Given its an ionic compound, you could probably just disassociate it with water. Or you could react it with a more electrophilic metal than Copper is.
It depends on what temperature they are heated to, if hot enough they could boil. They can also evaporate.
Copper sulfide. Depending on the valence of copper, you could have CuS or Cu2S
They could reach their melting point and melt or they could char and react with the oxygen in the atmosphere. Some solids will ignite when heated.
They could, since magnesium is more reactive than copper, and could displace it to form magnesium nitrate.
They used any weapons made of copper. (copper knife, sword, axe, anything copper they could get their hands on).