In group theory, there is exactly one group of order 5, which is the cyclic group ( \mathbb{Z}/5\mathbb{Z} ). This is because 5 is a Prime number, and any group of prime order is cyclic and isomorphic to the integers modulo that prime. Therefore, up to isomorphism, there is only one group with 5 elements.
Aristotle!:)
The d block has only 10 elements because the d sublevel can hold a maximum of 10 electrons due to its 5 orbitals, each with a paired electron. This results in a maximum of 5 d orbitals accommodating a total of 10 electrons in the d block elements.
'3d-, 4d-, 5d-, 6d-block' elements are in groups 3-12 in period 4, 5, 6 and 7 respectively.
Beryllium sulfite is composed of three elements: beryllium, sulfur, and oxygen.
Disjoint means they have no elements in common. The union is the set of elements containing all elements from both sets. Since there is no overlap, the union will have 5+7 elements. Therefore the answer is 12.
Considering also very heavy artificial elements this group doesn't exist.
5 groups of elements
There is a total of 17 elements in those groups.
4 groups of 10 = 40. 40 /5 = 8 so the answer is 8 groups of 5.
8,640 groups.
5
there are 5
5
There are 6 groups.
1 of 0 elements 5 of 1 elements 10 of 2 element 10 of 3 elements 5 of 4 elements 1 of 5 elements A total of 25 = 32 combinations.
Well, some website said that it was in group Va, but what is group Va?
There are 5C3 = 10 groups.