The short answer to your question is eight. Here is the long answer: SO3 has a total of 24 valence electrons. The central S is bonded to each of the O atoms. In the dot structure, one of the O atoms is double bonded to the S while the others have a single bond. This gives S its octet, using 8 of the valence electrons. The remaining 16 electrons exist as lone pairs. The two single bonded oxygens each have three lone pairs of electrons to obtain their octet. The double bonded oxygen has two lone pairs to obtain its octet. Since the double bond oxygen could be any of the three oxygens, the molecule is actually a combination of all three structures (the resonance structure).
There are 2 lone pairs in TeO3^2-.
In phosphine (PH3), there are three lone pairs and three bonding pairs.
Germanium (Ge) has 2 lone pairs of electrons.
The Si has no lone pairs, but each F has 6 lone pairs. Thus 6 x 4 = 24 lone pairs, total.
2
There are two lone pairs on XeF4.
There are 2 lone pairs in TeO3^2-.
No lone pairs
Germanium (Ge) has 2 lone pairs of electrons.
The H2O2 molecule has two lone pairs.
The molecule BeCl2 has zero lone pairs.
In phosphine (PH3), there are three lone pairs and three bonding pairs.
There are three lone pairs present in chlorine atom
3 Lone pairs and one unpaired electron
two bonds and eight lone pairs
The lone pairs are on the bromine atom- 3 in all.
There are two lone pairs on the arsenic atom in ASO2.