answersLogoWhite

0

What else can I help you with?

Continue Learning about Natural Sciences

What is the area of McKee Botanical Garden?

The area of McKee Botanical Garden is 72,843.4156032 square meters.


How many meters above sea level is Welwyn Garden City?

it is 5,900,894,673,800,674,135,790 miles above sea level


What is the distance around a circular track in meters if it diameter is 200?

To find the distance around a circular track, you can use the formula for the circumference, which is ( C = \pi \times d ), where ( d ) is the diameter. If the diameter is 200 meters, the circumference is ( C = \pi \times 200 \approx 628.32 ) meters. Therefore, the distance around the track is approximately 628.32 meters.


What unit would you measure to fence around a garden?

The unit you would use to measure the fencing around a garden is typically in linear units, such as feet or meters. This is because fencing is a one-dimensional measurement of the perimeter of the garden area. You would measure the length of each side of the garden and then add those measurements together to determine the total length of fencing needed.


At what angular velocity would the earth have to rotate about its axis for a body at the equator to feel no weight?

You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.

Related Questions

How much fencing is requred to enclose a circular garden whose radius is 25 meters?

50 pi meters


How much fencing is required to enclose a circular garden whose diameter is 84 meters?

To determine the amount of fencing required to enclose a circular garden, we need to calculate the circumference using the formula (C = \pi \times d), where (d) is the diameter. For a garden with a diameter of 84 meters, the circumference is (C = \pi \times 84 \approx 263.76) meters. Therefore, approximately 263.76 meters of fencing is required.


How much fencing is required to enclose a circular garden whose radius is 19 m use 3.14 as pi?

How much fencing is required to enclose a circular garden with a radius of 14 meters? (Use 3.14 for π) _


How much fencing is required to enclose a circular garden whose radius is 18 meters?

Fencing needed: 2*pi*18 = just over 113 meters


If a garden has a perimeter of 80 meters what is the area?

Without knowing the shape of the garden, it is not possible to determine the area based solely on the perimeter. The area of a garden depends on its shape, whether it is rectangular, square, circular, or irregular.


How much fencing is required to enclose a circular garden whose radius is 70 m?

To find the amount of fencing required to enclose a circular garden, you need to calculate the circumference of the circle. The formula for the circumference ( C ) is ( C = 2\pi r ), where ( r ) is the radius. For a garden with a radius of 70 m, the fencing required would be ( C = 2\pi(70) \approx 439.82 ) meters. Therefore, approximately 440 meters of fencing is needed.


A garden is 15 meters long and 12 meters wide what is the perimeter of the garden?

The perimeter is 54 meters.


What is the perimeter of the garden when a garden have 15 meters long and 12 meters wide?

The perimeter is 54 meters.


If a square garden with side lengths of 4 meters how many square meters is the garden?

16 square meters


A square garden has an area of 12.25 square meters. What is the perimeter of the garden?

Each side of the garden 3.5 meters and 4 times 3.5 = 14 meters which is the perimeter


The length of a rectangular garden is 4 meters more than 3 times its width the perimeter of the garden is 56m What are the dimensions of the garden?

length = 22 meters and width = 6 meters


What is the diameter of 220 meters circular pool?

diameter = 220/pi meters