Approx 25.13 metres.
The area of McKee Botanical Garden is 72,843.4156032 square meters.
it is 5,900,894,673,800,674,135,790 miles above sea level
To find the distance around a circular track, you can use the formula for the circumference, which is ( C = \pi \times d ), where ( d ) is the diameter. If the diameter is 200 meters, the circumference is ( C = \pi \times 200 \approx 628.32 ) meters. Therefore, the distance around the track is approximately 628.32 meters.
The unit you would use to measure the fencing around a garden is typically in linear units, such as feet or meters. This is because fencing is a one-dimensional measurement of the perimeter of the garden area. You would measure the length of each side of the garden and then add those measurements together to determine the total length of fencing needed.
You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.
50 pi meters
To determine the amount of fencing required to enclose a circular garden, we need to calculate the circumference using the formula (C = \pi \times d), where (d) is the diameter. For a garden with a diameter of 84 meters, the circumference is (C = \pi \times 84 \approx 263.76) meters. Therefore, approximately 263.76 meters of fencing is required.
How much fencing is required to enclose a circular garden with a radius of 14 meters? (Use 3.14 for π) _
Fencing needed: 2*pi*18 = just over 113 meters
Without knowing the shape of the garden, it is not possible to determine the area based solely on the perimeter. The area of a garden depends on its shape, whether it is rectangular, square, circular, or irregular.
To find the amount of fencing required to enclose a circular garden, you need to calculate the circumference of the circle. The formula for the circumference ( C ) is ( C = 2\pi r ), where ( r ) is the radius. For a garden with a radius of 70 m, the fencing required would be ( C = 2\pi(70) \approx 439.82 ) meters. Therefore, approximately 440 meters of fencing is needed.
The perimeter is 54 meters.
The perimeter is 54 meters.
16 square meters
Each side of the garden 3.5 meters and 4 times 3.5 = 14 meters which is the perimeter
length = 22 meters and width = 6 meters
diameter = 220/pi meters