1 megamole = 1 000 000 moles
the answer is there number of atoms
74 g magnesium (1 mole Mg/24.31 g)(6.022 X 1023/1 mole Mg)(1 mole Mg atoms/6.022 X 1023) = 3.0 moles of magnesium atoms ------------------------------------------- As you see Avogadro's number is over itself as a form of one, so only the moles of Mg need be found. This depiction is the formal set up.
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1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
C13H18O2 500 mg ibuprofen (1 gram/1000 mg)(1 mole ibuprofen/206.274 grams)(13 mole C/1 mole ibuprofen)(6.022 X 10^23/1 mole C) = 1.90 X 10^22 atoms of carbon in that mass ibuprofen
no it does not!
The formula weight of NaCl is 58.44 which means 58.44 g = 1 mole. Since 1000 mg = 1 g, this gives 58.44 g/mole x 1000 mg/g = 5.844 E+4 mg/mole. Then, 52.1 mg NaCl x 1 mole NaCl/5.844E+4 mg = 8.92 E-4 mole. See, this is just done by using the definitions of the units and the factor label method to analyze the conversion.
the answer is there number of atoms
The atomic mass of magnesium (Mg) is approximately 24.305 grams per mole.
74 g magnesium (1 mole Mg/24.31 g)(6.022 X 1023/1 mole Mg)(1 mole Mg atoms/6.022 X 1023) = 3.0 moles of magnesium atoms ------------------------------------------- As you see Avogadro's number is over itself as a form of one, so only the moles of Mg need be found. This depiction is the formal set up.
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Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
1 mole Mg = 6.022 x 1023 atoms 1 mole Mg = 24.3050g (atomic weight in grams) 1g Mg x (1mol/24.3050g) x (6.022 x 1023atoms/mol) = 2 x 1023 atoms (rounded to 1 significant figure)
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
To calculate the moles of gas produced, first find the moles of Mg reacting by dividing the mass by the molar mass of Mg. Next, determine the mole ratio of Mg to gas produced from the balanced chemical equation of the reaction. Finally, multiply the moles of Mg by the mole ratio to find the moles of gas produced.
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.