The density of water at 22oC is 0.99777 g/ml. So 1 ml would weigh 0.99777 g.
1 gram would be 1/0.99777 millilitres, which is 1.0022 ml.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
The freezing point of water is 0 degrees Celsius, and the boiling point is 100 degrees Celsius. Therefore, there are 100 degrees Celsius separating the two points.
32-degrees Fahrenheit. 0-Celsius is the freezing point of water, as is 32-degrees Fahrenheit
-180 degrees Celsius is -292 degrees Fahrenheit.
There are 100 degrees Celsius between the freezing point (0°C) and the boiling point (100°C) of water.
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
To raise 1 gram of water by 40 degrees Celsius, you need 40 calories. This is based on the specific heat capacity of water, which is approximately 1 calorie per gram per degree Celsius. Therefore, for a temperature increase of 40 degrees, you multiply 40 degrees by 1 calorie per gram.
1 degree celsius.
540 cal
To transform 1 gram of ice at 0 degrees Celsius to 1 gram of water vapor at 100 degrees Celsius, 720 calories are added (absorbed). There are no calories released during the process.
Zero Celsius
When 1 gram of liquid water at 0 degrees Celsius freezes to form ice, it releases 334 Joules of heat.
100 degrees Celsius.
100 degrees Celsius
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
To vaporize 1 gram of boiling water at 100 degrees Celsius, it would require approximately 2260 joules, which is equivalent to about 0.54 calories. This energy is needed to break the intermolecular bonds holding water molecules together, allowing them to escape into the gas phase.
Boiling point of water is 100 degrees Celsius.