To find the volume of a 1.5% glucose solution that contains 125 grams of glucose, first calculate the amount of glucose in 1 mL of the solution. A 1.5% solution means there are 1.5 grams of glucose in 100 mL. Therefore, to find the volume for 125 grams, use the proportion: ( \frac{125 \text{ grams}}{1.5 \text{ grams/100 mL}} = \frac{125 \times 100}{1.5} ), which equals approximately 8333.33 mL. Thus, 125 grams of glucose is contained in about 8333.33 mL of a 1.5% glucose solution.
A 1 M (molar) solution of glucose contains 1 mole of glucose per liter (1000 ml). Therefore, in 350 ml of a 1 M glucose solution, there are 0.35 moles of glucose. The molar mass of glucose (C6H12O6) is approximately 180 g/mol, so the amount of glucose in 350 ml is 0.35 moles × 180 g/mol = 63 grams.
how many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
You need 0,9 glucose.
Many chemists (not all) consider this solution as hypotonic.
The solution is 0,25 M.
A 1 M (molar) solution of glucose contains 1 mole of glucose per liter (1000 ml). Therefore, in 350 ml of a 1 M glucose solution, there are 0.35 moles of glucose. The molar mass of glucose (C6H12O6) is approximately 180 g/mol, so the amount of glucose in 350 ml is 0.35 moles × 180 g/mol = 63 grams.
0.275578 pounds
1 mole of glucose contains 6.022 x 10^23 molecules. In a 1 M solution, there would be 1 mole of glucose dissolved in 1 liter of solution, so there would be 6.022 x 10^23 molecules of glucose in 1 liter of the solution.
how many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
1 gram = 1ooo milligrams Mills is in slang.
To find the mass of glucose in the solution, we first need to calculate the volume of glucose in the solution. Using the formula m = V x mv, we find that the mass of glucose (m) in 205 mL of a 5.50 mv glucose solution is approximately 11.28 grams.
There are 1,000 milligrams (mg) in a gram. Therefore, if you have 1 gram of glucose, it contains 1,000 mg of glucose.
You need 0,9 glucose.
Many chemists (not all) consider this solution as hypotonic.
The solution is 0,25 M.
Concentrated
There are 12.