A concentration of 110 M or 106 M doesn't exist.
baoh2
To calculate the number of moles of Ba(OH)2 present in 125 mL of 8.00 M Ba(OH)2 solution, you can use the formula: moles = molarity x volume (in liters). First, convert 125 mL to liters (0.125 L), then multiply 8.00 M by 0.125 L to get 1.00 moles of Ba(OH)2.
Barium hydroxide (Ba(OH)2) has 3 atoms: 1 barium atom (Ba) and 2 hydroxide groups, each consisting of 1 oxygen atom (O) and 1 hydrogen atom (H).
This solution is impossible because the solubility of Ba(OH)2 at 20 0C is only 38,9 g/L.
Ba(OH)2 (barium hydroxide) would increase the pH of water when dissolved because it is a strong base that releases hydroxide ions, which react with water to produce more OH- ions, thus increasing the pH. NaCl (sodium chloride) would not significantly affect the pH of water when dissolved because it dissociates into Na+ and Cl- ions, which do not influence the pH of the solution.
baoh2
NaOH is a strong base because it dissociates completely in water to produce hydroxide ions. NH3 is a weak base because it only partially ionizes in water. Ba(OH)2 is a strong base because it dissociates completely to produce hydroxide ions. HF is a weak base because it only partially ionizes in water.
Yes. Barium hydroxide, Ba(OH)², undergoes complete disassociation of its ions in water (Ba++ and 2 OH-).
Yes, because it is a base.
Barium hydroxide - Ba(OH)2 - is a hydroxide.
To neutralize the Ba(OH)2, we need an equal number of moles of HCl. The molarity of Ba(OH)2 is 0.200 mol/dm^3, so the number of moles present in 25.0 cm^3 is (0.200 mol/dm^3) x (25.0 cm^3 / 1000 cm^3) = 0.005 mol. Since HCl and Ba(OH)2 neutralize each other in a 1:1 ratio, we need the same number of moles of HCl. Therefore, the volume of 0.200 mol/dm^3 HCl needed is (0.005 mol) / (0.200 mol/dm^3) = 0.025 dm^3, which is equivalent to 25.0 cm^3.
Barium hydroxide IS soluble in water, and it has the formula Ba(OH)2, not ba(oh)2.
Yes. Barium hydroxide, Ba(OH)², undergoes complete disassociation of its ions in water (Ba++ and 2 OH-).
To calculate the number of moles of Ba(OH)2 present in 125 mL of 8.00 M Ba(OH)2 solution, you can use the formula: moles = molarity x volume (in liters). First, convert 125 mL to liters (0.125 L), then multiply 8.00 M by 0.125 L to get 1.00 moles of Ba(OH)2.
Yes, ( \text{Ba(OH)_2} ) is considered an electrolyte because it dissociates into ions (( \text{Ba}^{2+} ) and ( 2\text{OH}^- )) when dissolved in water, allowing it to conduct electricity.