One molecule has only one C atom.So 0.56mol has 0.56mol of C atoms
Methane is an elementary organic compound having the molecular formula of CH4. Methane is composed of carbon (C) and hydrogen (H) atoms. The molecular weight of CH4 is 16. 01 grams per mole.
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
C ( carbon ) = 12.01 grams/moleH ( hydrogen ) = 1.008 grams/mole * 4------------------------------------------------------------add= 16.042 grams/mole===============
CH4's melting point is -182 C. In the context of the usual type of question about melting points, CH4 has a very low melting point because the attractions between CH4 molecules are very weak.
To calculate the energy produced, you need to know the enthalpy change for the reaction. Once you have that information, you can use the equation Q = mcΔT, where Q is the energy produced, m is the mass of CH4, c is the specific heat capacity of CH4, and ΔT is the temperature change.
Moles of methane. No half molecules, I think! 2.50 moles methane (1 mole C/1 mole CH4)(6.022 X 1023/1 mole C) = 1.51 X 1024 molecules of carbon --------------------------------------------
There are 0.75 moles in it.You have to devide 12 by molecular mass
CH4 --> CO2 is a 1 to 1 reaction (C-balanced) when burning with oxygen. So 1 mole CH4 --> 1 mole CO2 So 1 Litere CH4 --> 1 Liter CO2 So 16 grams CH4 --> 44 grams CO2
Methane is an elementary organic compound having the molecular formula of CH4. Methane is composed of carbon (C) and hydrogen (H) atoms. The molecular weight of CH4 is 16. 01 grams per mole.
The balanced equation for the reaction of C + 2H2 → CH4 is: C + 2H2 → CH4. This equation is already balanced. Each side has 1 carbon atom and 4 hydrogen atoms.
To balance the equation CH4 + O2 -> CO2 + H2O, you would need a=1, b=2, c=1, and d=2. This is because you need 1 mole of CH4 reacting with 2 moles of O2 to produce 1 mole of CO2 and 2 moles of H2O.
It is propane
Answer 1CH4
C8h18 + 3h2 ---> ch4 + 2c2h6 + c3h8 All these C's and H's are supposed to be capitalized. -- Some computer keeps changing them.
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
169 g C x 1 mole C/12.011 g x 6.02x10^23 atoms/mole = 8.47x10^24 atoms
C ( carbon ) = 12.01 grams/moleH ( hydrogen ) = 1.008 grams/mole * 4------------------------------------------------------------add= 16.042 grams/mole===============