First write out the equation and balance it.
Then look at the ratio of C8H10 to CO2 produced in the reaction (hint: use molecular weights).
For example:
2A = 1B + 1C
where A =4, B=5, and C=3
so, for every 8g of A you get 5g of B
20g of B will yield 20 x 5/8 = 12.5g
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
To find the number of molecules in 18 grams of water (H₂O), we first determine the number of moles. The molar mass of water is approximately 18 g/mol. Therefore, 18 grams of water corresponds to 1 mole. Since one mole contains Avogadro's number of molecules, which is about (6.022 \times 10^{23}), there are approximately (6.022 \times 10^{23}) molecules in 18 grams of water.
That is 90 grams.
A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.
1 ounce = 28.35 grams 18 grams = 18/28.35 = 0.635 ounces The formula: 18 g* 1 oz 28.34952313 g = 0.6349313151 oz
The balanced equation for the complete combustion of C18H36 is: C18H36 + 25.5 O2 → 18 CO2 + 18 H2O. This equation shows that every molecule of C18H36 reacts with 25.5 molecules of O2 to produce 18 molecules of CO2 and 18 molecules of H2O.
The molar mass of water (H2O) is approximately 18 grams/mol. Therefore, for 4 molecules of water, the total mass would be 4 x 18 = 72 grams.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
To find the number of molecules in 18 grams of water (H₂O), we first determine the number of moles. The molar mass of water is approximately 18 g/mol. Therefore, 18 grams of water corresponds to 1 mole. Since one mole contains Avogadro's number of molecules, which is about (6.022 \times 10^{23}), there are approximately (6.022 \times 10^{23}) molecules in 18 grams of water.
Each mole of a substance contains 6.022 E23 molecules or atoms of that substance. Four moles of H2O will contain 2.4088 E24 molecules.
You would take your grams divided by the FW (formula weight) of the molecule. example: 1g of H2O divided by 18 = .056mol H2O you find the formula weight by adding of the atomic masses of each element O=16 and H=1 1(2)+16=18
To find the number of atoms in 110 grams of CO2, you first need to determine the number of moles by dividing the mass by the molar mass of CO2 (44.01 g/mol). Next, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, there are approximately 2.5 x 10^24 atoms in 110 grams of CO2.
18 pounds is 8164.66 grams.
18 kg = 18000 grams
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
18 grams