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This is another calculation. there are 0.123 moles inn this volume.

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9y ago

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How Many Moles of air are there in a 3 L container of 1 ATM pressure and 293?

0.125 moles


How many moles are there in a 3 L container at 1 ATM pressure and 293 K?

The answer is 0,125 moles.


How many moles of air are there in a 3 L container a 1 ATM pressure and 293 K?

0.125 moles


How many moles of air are there in a 3 L container at 1 am pressure and 293 K?

Air is a mixture.


How many moles of air there in a 3 L container at 1 ATM pressure and 293 K?

You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.


How many moles of air are there in 3 L container at 1 ATM pressure and 293 K?

3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles


The gaseous product of a reaction is collected in a 25.0-L container at 27C The pressure in the container is 300.0 kPa and the gas has a mass of 96.0 g How many moles of the gas are in the container?

You can use the ideal gas law, PV = nRT, to solve for the number of moles, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Rearrange the formula to solve for n, n = (PV) / (RT). Convert the temperature from Celsius to Kelvin (27°C + 273 = 300 K), and plug in the values to find the number of moles of the gas in the container.


A sample of nitrogen gas is confined to a 14.0 L container at 375 torr and 37 degrees Celsius How many moles of nitrogen are in the container?

To calculate the number of moles of nitrogen gas in the container, you can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Convert the pressure to atm, the volume to L, and the temperature to Kelvin. Then plug in the values and solve for n.


How many moles of the gas are in the container with a gas in a closed container has a pressure of 2.62 ATM a volume of 47.8 L and a temperature of 775 K.?

You solve this using the ideal gas law: PV = nRT and solve for n (moles)n = PV/RT = (2.62 atm)(47.8 L)/(0.0821 Latm/Kmol)(775K) n = 1.97 moles (3 significant figures)


How many moles of air are there in a 3 l container at 1 ATM pressure and 293 k?

3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles


How many moles of air are there in a 3 L container at 1 ATM pressure of 293 K?

Using the ideal gas law (PV = nRT), we can calculate the number of moles of air in the container. Rearranging the formula to solve for n (moles), we get n = (PV) / (RT). Plugging in the values (P = 1 atm, V = 3 L, R = 0.0821 Latm/molK, T = 293 K) and solving for n gives us approximately 0.12 moles of air.


A container with a volume of 564 L holds how many moles of air at STP?

1 mole of gas occupies 22.4 liters at STP. 564/22.4 = 25.18 moles (2 decimal places)