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To answer this, we must first know what STP is. STP (Standard Temperature and Pressure) is when the environment is at the following:
- 0oC
- 1 Atmosphere of Pressure (101.325 kPa)
To figure out any missing units in a gas equation, we use the Ideal Gas Law, PV=nRT.
- 'P' is pressure in kPa
- 'V' is volume in litres or dm3
- 'n' is the number of mol
- 'R' is the gas constant = 8.314
- 'T' is temperature in kelvin
To work out the number of mol, we substitute in the calues we have and solve for n. This gives us 101.325kPa*5.6dm3=n*8.314*273K. Therefore, n=0.25 mol.
Alternatively, we could simply use the fact that 1 mol of any gas at STP takes up 22.4 litres. So 5.6/22.4 leaves us with 0.25 mol.
What else can I help you with?
How many moles of argon gas Ar are present in 5.6 liters of argon gas at standard conditions?
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
How many moles of HCl are present in 0.70 liters of a 0.33 M HCl solution?
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
How many moles of KMnO4 are present in 75.0 mL of a 0.0950 M solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
How many moles of argon are in 37.9 g of argon?
To find the number of moles of argon in 37.9 g, you need to use the molar mass of argon, which is 39.95 g/mol. Divide the given mass by the molar mass to get the number of moles. So, 37.9 g / 39.95 g/mol = 0.95 moles of argon.
How many moles of argon gas Ar are present in 5.6 liters of argon gas at standard conditions?
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
How many moles are present in 8.4 liters of nitrous oxide at STP?
8,4 liters of nitrous oxide at STP contain 2,65 moles.
How many moles of helium gas (he) are present in 7.2 liters of helium gas at standard conditions?
The number of moles of helium is 0,32.
How many moles of gas are present when the volume of gas is 100.0 liters the pressure is 3 atmospheres and temperature is -10C?
The answer is 13,89 moles.
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
How many moles of HCl are present in 0.70 liters of a 0.33 M HCl solution?
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
How many moles of KCL are present in 50.0ml of a 0.552 M solution?
To determine the number of moles of KCl present in a solution, you need to use the formula: moles = molarity x volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (50.0 mL = 0.050 L). Then, calculate the moles of KCl by multiplying the molarity (0.552 M) by the volume in liters (0.05 L). This gives you approximately 0.0286 moles of KCl in the solution.
How many moles of argon are in 1.67 x 1024 atoms?
1,67.1024 argon atoms is equal to 2,773 moles.
How many moles of KMnO4 are present in 75.0 mL of a 0.0950 M solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
How many moles of argon are in 37.9 g of argon?
To find the number of moles of argon in 37.9 g, you need to use the molar mass of argon, which is 39.95 g/mol. Divide the given mass by the molar mass to get the number of moles. So, 37.9 g / 39.95 g/mol = 0.95 moles of argon.
How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?
The answer is approx. 2 moles (for anhydrous sodium sulfate).
How many moles of argon are found in a 5L sample of argon at STP?
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
