There is no nitrogen in water.
There are 0.003659 N2O moles. So there are o.007318 moles of N.
To produce potassium nitride (K₃N), the balanced chemical equation is 6 K + N₂ → 2 K₃N. This indicates that 6 moles of potassium are required to produce 2 moles of potassium nitride. Therefore, to produce 2.0 moles of K₃N, you would need 6 moles of potassium.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
Use this equation M.(H2O)m+n = M.(H2O)m-1OH +(n-1) + H+
To find the number of moles of nitrogen in 89.0 g of N₂O, first determine the molar mass of N₂O, which is approximately 44.01 g/mol (with nitrogen contributing about 28.02 g and oxygen about 16.00 g). Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we calculate the moles of N₂O: ( \frac{89.0 , \text{g}}{44.01 , \text{g/mol}} \approx 2.02 , \text{moles of N₂O} ). Since each molecule of N₂O contains two nitrogen atoms, the total moles of nitrogen is ( 2.02 \times 2 \approx 4.04 ) moles of nitrogen (N).
There are 0.003659 N2O moles. So there are o.007318 moles of N.
The answer is 0,0043 moles of N2.
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
n is the number of moles.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
Number of moles are calculated using the equation n=m/M where n is the number of moles, m is the mass of the substance and M is the molar mass of the substance. Molar mass of water = 18 g mol-1 Number of moles of water = 3.8 g /18 g mol-1 = 0.21 mol Number of moles of H in H2O =2 (the subscript next to the chemical symbol of an element indicates the number of moles of that element in that molecule) Number of moles of H in 3.8 g of H2O = 2 x 0.21 mol = 0.42 mol
n is number of moles per unit length and N is number of moles.
To find the number of moles of N in N2O, we need to use the molar mass of N2O. The molar mass of N2O is 44.02 g/mol. First, calculate the moles of N2O: 0.189g / 44.02 g/mol = 0.0043 moles of N2O Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N is: 0.0043 moles * 2 = 0.0086 moles of N.
Mass of BaCl2 = crucible + lid + BaCl2.nH2O - empty crucible + lidMass of water contained in hydrated BaCl2: Initial mass - final massNo. of moles of H2O in hydrated salt = No. of moles = mass of H2O/formula mass of H2O Use this answer in ratioNo. of moles of BaCl2 in 3.399 g = No. of moles = mass of BaCl2/formula mass of BaCl2 Use this answer in ratioThe ratio of BaCl2 to H2O is 1 : 2
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
Use this equation M.(H2O)m+n = M.(H2O)m-1OH +(n-1) + H+