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How many moles of air are there in a 3 L container a 1 ATM pressure and 293 K?
0.125 moles
How many moles of air there in a 3 L container at 1 ATM pressure and 293 K?
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
How many moles of air are there in a 3L container at 1 ATM pressure and 293 K?
To find the number of moles of air in a 3L container at 1 ATM pressure and 293 K, we can use the ideal gas law, PV = nRT. Here, P = 1 ATM, V = 3 L, R = 0.0821 L·ATM/(K·mol), and T = 293 K. Rearranging the formula to solve for n gives us n = PV / RT. Substituting the values, we get n = (1 ATM)(3 L) / (0.0821 L·ATM/(K·mol) * 293 K) ≈ 0.124 moles of air.
How many moles of air are there in a 3 L container at 1 am pressure and 293 K?
Air is a mixture.
If 4 moles of gas are added to a container that already holds 1 mole of gas the pressure inside the container what due to the change in the amount of gas?
To answer this question you first need to know how big the container is. What is the volume of the container?
How Many Moles of air are there in a 3 L container of 1 ATM pressure and 293?
0.125 moles
How many moles of air are there in a 3 L container a 1 ATM pressure and 293 K?
0.125 moles
How many moles of air there in a 3 L container at 1 ATM pressure and 293 K?
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
How many moles of air are there in a 3 L container at 1 ATM pressure of 293 K?
Using the ideal gas law (PV = nRT), we can calculate the number of moles of air in the container. Rearranging the formula to solve for n (moles), we get n = (PV) / (RT). Plugging in the values (P = 1 atm, V = 3 L, R = 0.0821 Latm/molK, T = 293 K) and solving for n gives us approximately 0.12 moles of air.
How many moles of air are there in 3 L container at 1 ATM pressure and 293 K?
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
How many moles of air are there in a 3L container at 1 ATM pressure and 293 K?
To find the number of moles of air in a 3L container at 1 ATM pressure and 293 K, we can use the ideal gas law, PV = nRT. Here, P = 1 ATM, V = 3 L, R = 0.0821 L·ATM/(K·mol), and T = 293 K. Rearranging the formula to solve for n gives us n = PV / RT. Substituting the values, we get n = (1 ATM)(3 L) / (0.0821 L·ATM/(K·mol) * 293 K) ≈ 0.124 moles of air.
How many moles of air are there in a 3 l container at 1 ATM pressure and 293 k?
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
How many moles of air are there in a 3 l container at 1 ATM pressure and 2933 k?
To determine the number of moles of air in the container, we need to use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for n, we get n = PV / RT. Plugging in the values (P = 1 atm, V = 3 L, T = 293 K, R = 0.0821 L.atm/mol.K), we find n = (1 atm * 3 L) / (0.0821 L.atm/mol.K * 293 K) = 0.123 moles.
How many moles of air are there in a 3 L container at 1 am pressure and 293 K?
Air is a mixture.
A container with a volume of 564 L holds how many moles of air at STP?
1 mole of gas occupies 22.4 liters at STP. 564/22.4 = 25.18 moles (2 decimal places)
How many moles of oxygen are present in the air?
The amount of oxygen in the air is about 0.21 moles per liter.
If 4 moles of gas are added to a container that already holds 1 mole of gas the pressure inside the container what due to the change in the amount of gas?
To answer this question you first need to know how big the container is. What is the volume of the container?
