0.8 mol
To calculate the mass of aluminum (Al) needed to completely react with 135 g of iron, you first need to determine the molar ratio between them from the balanced chemical equation. The balanced equation for the reaction between aluminum and iron is 2Al + 3Fe2O3 -> 3Fe + Al2O3. From this ratio, you can calculate that 2 moles of aluminum (Al) react with 3 moles of iron (Fe). Next, calculate the molar mass of aluminum (Al) and use it to convert the given mass of iron to moles. Finally, use the molar ratio to find the mass of aluminum needed.
These reagents doesn't react.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
1 mole sulfuric acid for 1 mole calcium chloride
To calculate the mass of aluminum (Al) needed to completely react with 135 g of iron, you first need to determine the molar ratio between them from the balanced chemical equation. The balanced equation for the reaction between aluminum and iron is 2Al + 3Fe2O3 -> 3Fe + Al2O3. From this ratio, you can calculate that 2 moles of aluminum (Al) react with 3 moles of iron (Fe). Next, calculate the molar mass of aluminum (Al) and use it to convert the given mass of iron to moles. Finally, use the molar ratio to find the mass of aluminum needed.
These reagents doesn't react.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
The balanced chemical equation for the reaction between iron oxide (Fe2O3) and aluminum (Al) is 2Al + Fe2O3 → Al2O3 + 2Fe. This shows that 2 moles of Al react with 1 mole of Fe2O3. Therefore, 2.5 moles of Al would need 1.25 moles of Fe2O3 to completely react.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
0.8 moles Explanation: from the equation we can see, 2 mole A l is needed to react completely with 3 mole F e O so, 3 moles of F e O needs 2 moles A l so, 1 mole F e O needs 2 3 moles A l so, 1.2 mol F e O needs 2 × 1.2 3 moles A l = 0.8 moles A l
This is a mole stoichiometry problem. Start with the balanced equation for the synthesis of aluminum oxide: 4Al + 3O2 --> 2Al2O3. The ratio of aluminum to aluminum oxide in this equation is 4:2, or 2:1, so 5.23 moles Al means half that number for Al2O3, so about 2.62 moles of aluminum oxide will be produced.