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What is the chemical formula of selenium tetrafluoride?
The chemical formula of selenium tetrafluoride is SeF4.
How many moles are in 56 micrograms of selenium?
First, we need to convert micrograms to grams by dividing by 1,000,000. Then, we can use the molar mass of selenium (78.971 g/mol) to find the number of moles. So, 56 micrograms of selenium is equal to 0.000056 grams, which corresponds to approximately 7.07 x 10^-7 moles of selenium.
What is the hybridization of selenium Tetrafluoride?
sp3d. For each energy level (s,p,d,f) there are a certain amount of atoms in that section. S has 2. Divide it by two, you get one. P has 6. Divide it by 2, you get 3, and so on. Because selenium tetrafluoride has 5 things around it (four fluorides and a lone pair), it will go up to 5, which is sp3d.
What is the molarity of a 5ml solution containing 0.7 micrograms of selenium?
The answer is1.77 * 10-6 M.Solution:.7 ug * (1 g \ 106 ug) This converts our value from micrograms (ug) to grams (g).* (1 mole Selenium \ 78.96 g Selenium) This gives out our # of moles Selenium by using Selenium's molar mass (78.96 g/mol).= 8.87 * 10-9 moles SeleniumDivided by the volume in liters (.005 L)= 1.77 * 10-6 moles Selenium \ 1 L (M)Check:.005 L * (1.77 * 10-6 moles Selenium\ 1 L)= .00000177 moles Selenium* (78.96 g Selenium \ 1 mole Selenium)* (106 ug \ 1 g)~= .7 ug.- Mike
A compound containing selenium and fluorine is decomposed in the laboratory and produces 2.231 of selenium and 3.221 of fluorinCalculate the empirical formula of the compound e?
The answer is SeF6.This is figured by:2.231 grams of Se divided by 78.79 g/mol = 0.0283 moles of Se3.221 grams of F divided by 18.998 g/mol = 0.1695 moles of F0.1695 moles of Se/0.0283 moles of F = 5.9909 ~ 6 moles of Se/mole of FSo SeF6
What is the chemical formula of selenium tetrafluoride?
The chemical formula of selenium tetrafluoride is SeF4.
What is the name of the compound SeF4?
The compound SeF4 is called selenium tetrafluoride.
What is the name of SeF4 in chemestry?
Selenium tetrafluoride.
How many ATOMS of carbon are present in 3.27 moles of carbon tetrafluoride?
Since there is one carbon atom per mole in carbon tetrafluoride, the answer is 3.27 times Avogadro's Number or about 1.97 X 1024 atoms.
How many moles are in 56 micrograms of selenium?
First, we need to convert micrograms to grams by dividing by 1,000,000. Then, we can use the molar mass of selenium (78.971 g/mol) to find the number of moles. So, 56 micrograms of selenium is equal to 0.000056 grams, which corresponds to approximately 7.07 x 10^-7 moles of selenium.
What is the hybridization of selenium Tetrafluoride?
sp3d. For each energy level (s,p,d,f) there are a certain amount of atoms in that section. S has 2. Divide it by two, you get one. P has 6. Divide it by 2, you get 3, and so on. Because selenium tetrafluoride has 5 things around it (four fluorides and a lone pair), it will go up to 5, which is sp3d.
What is the molarity of a 5ml solution containing 0.7 micrograms of selenium?
The answer is1.77 * 10-6 M.Solution:.7 ug * (1 g \ 106 ug) This converts our value from micrograms (ug) to grams (g).* (1 mole Selenium \ 78.96 g Selenium) This gives out our # of moles Selenium by using Selenium's molar mass (78.96 g/mol).= 8.87 * 10-9 moles SeleniumDivided by the volume in liters (.005 L)= 1.77 * 10-6 moles Selenium \ 1 L (M)Check:.005 L * (1.77 * 10-6 moles Selenium\ 1 L)= .00000177 moles Selenium* (78.96 g Selenium \ 1 mole Selenium)* (106 ug \ 1 g)~= .7 ug.- Mike
How do you convert 2.76 g SE to moles SE?
To convert grams of selenium (Se) to moles, divide the given mass by the molar mass of selenium. The molar mass of selenium is approximately 78.97 g/mol. ( \dfrac{2.76 : g}{78.97 : g/mol} = 0.035 : mol : Se)
How many ATOMS of nitrogen are present in 4.19 moles of dinitrogen tetrafluoride?
The chemical name dinitrogen tetrafluoride establishes that each molecule contains exactly 2 nitrogen atoms. A mole always contains Avogadro's Number of molecules. Therefore, the required answer is 4.19 X 2 X Avogadro's Number, or 5.05 X 1024 atoms, to the justified number of significant digits.
A compound containing selenium and fluorine is decomposed in the laboratory and produces 2.231 of selenium and 3.221 of fluorinCalculate the empirical formula of the compound e?
The answer is SeF6.This is figured by:2.231 grams of Se divided by 78.79 g/mol = 0.0283 moles of Se3.221 grams of F divided by 18.998 g/mol = 0.1695 moles of F0.1695 moles of Se/0.0283 moles of F = 5.9909 ~ 6 moles of Se/mole of FSo SeF6
How many molecules of sulfur tetrafluoride are present in 2.13 moles of this compound?
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
How many atoms are there in 30.4 g of selenium?
To determine the number of atoms in 30.4 g of selenium, you first need to calculate the number of moles using the molar mass of selenium (78.97 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in that amount of selenium. In this case, there are approximately 3.86 x 10^22 atoms in 30.4 g of selenium.
