It depends on the genetics of the parents. If both parents carry a short gene, then all the offspring would have a chance of being short. If only one parent carries the short gene, then approximately half of the offspring would be short.
When Mendel crossed short tt pea plants (homozygous recessive) with short pea plants that were heterozygous for height (Tt), the offspring would display a phenotypic ratio of 1 short (tt) to 1 tall (Tt). This is because the short plants (tt) can only contribute recessive alleles, while the heterozygous plants (Tt) can contribute either a dominant (T) or a recessive (t) allele. Therefore, half of the offspring would be tall and half would be short.
The Punnett square would show that all offspring would be heterozygous for the trait, meaning they would have one allele for tall plants and one allele for short plants. This would result in all offspring being tall plants phenotypically, but carrying the allele for short plants.
tall and short
You would expect a 1:1 ratio of offspring with a long body (LL) to offspring with a short body (ll) due to the incomplete dominance of the gene for body length in Drosophila.
When a heterozygous long-winged fly (LW) is crossed with a short-winged fly (ww), the possible genotypes of the offspring are LW and ww. This results in a 50% chance of producing long-winged offspring (LW) and a 50% chance of producing short-winged offspring (ww). Therefore, there is a 50% likelihood that the offspring will have long wings.
The Punnett square would show that all offspring would be heterozygous for the trait, meaning they would have one allele for tall plants and one allele for short plants. This would result in all offspring being tall plants phenotypically, but carrying the allele for short plants.
no. in the second generation it will have a short offspring , but in the first generation it will have tall offspring
3
If eastern cougars did not have offspring, they would become extinct. They have one or two at a time.
You would expect a 1:1 ratio of offspring with a long body (LL) to offspring with a short body (ll) due to the incomplete dominance of the gene for body length in Drosophila.
good stuff
An F1 x F1 cross would be a cross between heterozygous (Tt) parents. The offspring would be 1/4 TT, 1/2 Tt, and 1/4 tt. This would mean that 3/4 of the offspring would be tall, and 1/4 would be short.These offspring would be the F2 generation. Click on the related link to see an illustration of this using Punnett squares.
The combination of a female offspring would be XX
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It would depend on the dominant gene: I would compare the mother's parents eyelashes to the father's parents eyelashes, for each of the parent's eyelashes that are long it is an increase in 25% that the offspring will have long eyelashes. Unless half of the father's parents have long lashes then that shows the short lash gene is dominant.
The ratio produced would be 1:1 for heterozygous (Tt) offspring to homozygous recessive (tt) offspring. This is because the parent with genotype Tt will pass on one dominant allele (T) and one recessive allele (t) to its offspring, resulting in a 50% chance of either genotype in the offspring.
If the gene for colored spots was not passed from a moth to its offspring, the offspring would not have colored spots. Traits are inherited from parents through genes, so without the gene for colored spots, the offspring would not exhibit this specific physical characteristic.