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How many node are present in 4f orbital?

There are 3 nodes present in a 4f orbital: one radial node and two angular nodes. This means that there are regions in the orbital where the probability of finding an electron is zero.


How many electrons are in the n1 shell?

There can be 10 electrons in the n=2 shell. Two can fit in the 1s orbital, two can fit in the 2s orbital, and six can fit in the 2p orbital.


Codings for coprime number in c?

#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }


How is an unoccupied orbital represented in orbital notation?

An unoccupied orbital is represented by an empty box in orbital notation. It does not have any electrons present in it but is available to accept electrons if needed.


What is the pmf of trinomial distribution?

P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n


How many hours from cape town to durban on n1?

With greyhond


What is the value of the expression of n1?

the value of the exponent n1


What is the value of the expression n1?

the value of the exponent n1


Find LCM and HCF of two given number by using for loop in c?

#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }


How many 3d electron found in Tin?

In the electron configuration of tin (Sn), the 3d electrons are not present. Tin has a configuration of [Kr] 5s2 4d10 5p2, which means it has 2 electrons in the 5s orbital, 10 electrons in the 4d orbital, and 2 electrons in the 5p orbital.


How many orbitals are in d orbital orbital?

five


How can you create calculator in computer language cpp?

void main() { int i; float n1,n2; abc: printf("Enter two nos "); scanf("%f%f",&n1,&n2); printf("\n %f + %f = %f " ,n1,n2,n1+n2); printf("\n %f - %f = %f " ,n1,n2,n1-n2); printf("\n %f x %f = %f " ,n1,n2,n1*n2); printf("\n %f / %f = %f " ,n1,n2,n1/n2); printf("\npress 5 to make another calculation"); scanf("%d",&i); if (i==5) goto abc; }