The molecular weight of carbon monoxide (CO) is 28.01 grams per mole. It is calculated by adding the atomic weights of carbon (12.01 g/mol) and oxygen (16.00 g/mol).
17 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 8.5 X 1023 atoms of carbon =====================
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ration of isotopes equal to that in nature - has a mass of 12.0107 grams.
8.20g of carbon monoxide, how many grams of methanol will be produced?
Carbon monoxide is created by incomplete combustion by lack of oxygen:2C2H5OH + 5O2 --> 2CO + 2CO2 + 6H2Oin stead of2C2H5OH + 6O2 --> .. + 4CO2 + 6H2Owhich is the same as, correctly written (by dividing by 2): C2H5OH + 3O2 --> 2CO2 + 3H2O
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
The molecular weight of carbon monoxide (CO) is 28.01 grams per mole. It is calculated by adding the atomic weights of carbon (12.01 g/mol) and oxygen (16.00 g/mol).
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
In 52.06g of carbon dioxide (CO2), you have 1 mole of CO2, which contains 2 moles of oxygen atoms. Each mole of oxygen atoms is equivalent to 6.022 x 10^23 atoms. Therefore, in 52.06g of CO2, there are 2 x 6.022 x 10^23 oxygen atoms.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
There are approximately 3.633 x 10^23 carbon atoms in 21.84 grams of carbon.
Balanced equation always and first. Decomposition reaction. CO2 -> C + O2 440 grams CO2 (1 mole CO2/44.01 grams)(1 mole O2/1 mole CO2)(32 grams/1 mole O2) = 319.93 grams O2 ( call it 320 grams )
31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================
Carbon monoxide (CO) and carbon dioxide (CO2) have a molar ratio of 1:1 with respect to carbon. The molar mass of CO is 28 g/mol and the molar mass of CO2 is 44 g/mol. Since the same mass of carbon reacts in both cases, the same mass of oxygen (13.6 g) would react to form CO2.