In the reactant aluminum phosphate (AlPO₄), there is one oxygen atom per formula unit. Since there are two formula units of AlPO₄ in the balanced reaction (2AlPO₄), the total number of oxygen atoms is 2 × 4 = 8 oxygen atoms.
In a complete and correctly balanced chemical equation you will have the coefficients for each reactant and product indicating the mole ratios as well as the phases of each reactant and product.
First, calculate the moles of each reactant. Next, determine which reactant is the limiting reactant by comparing the moles of each reactant to the stoichiometry of the balanced chemical equation. The reactant that produces the least amount of product based on stoichiometry is the limiting reactant.
To find the limiting reactant in a reaction, calculate the moles of each reactant present. Compare the moles of each reactant to the stoichiometry of the balanced chemical equation to see which reactant runs out first. Whichever reactant produces the least amount of product is the limiting reactant.
from a balanced chemical equation
In a balanced chemical equation, a reaction is the process of converting reactants into products. Each reactant molecule is transformed into a set of corresponding product molecules according to the stoichiometric coefficients in the balanced equation.
The reactant aluminum phosphate has a chemical formula AlPO4. There are 4 oxygen atoms in one molecule of aluminum phosphate.
The balanced equation for the reaction between aluminum nitrate and ammonium phosphate is: 2Al(NO3)3 + 3(NH4)3PO4 → 2AlPO4 + 6NH4NO3
3Al(C2H3O2)3 + 2K3PO4 -> 2AlPO4 + 6KC2H3O2
(NH4)2CO3 + MgSO4 = (NH4)2SO4 + MgCO3 olrite?
(NH4)3PO4+AlCl3------->3NH4Cl+AlPO4
The balanced equation is: 2Al(C2H3O2)3(aq) + 3(NH4)3PO4(aq) → AlPO4(s) + 6NH4C2H3O2(aq)
The balanced neutralization reaction between phosphorus acid (H3PO3) and aluminum hydroxide (Al(OH)3) produces aluminum phosphate (AlPO4) and water (H2O). The balanced chemical equation is: 2H3PO3 + 3Al(OH)3 → 2AlPO4 + 6H2O
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
Al(C2H3O2)3 + K3PO4 ==> AlPO4 + 3 C2H3O2Kor looked at another way... Al(CH3COO)3 + K3PO4 ==> AlPO4 + 3 CH3COOK
The formula of aluminium chloride is AlCl3. The atomic weight of aluminium is 27 and that of chlorine is 35.5. That means 35.5*3 grams of chlorine will combine with 27 grams of aluminium. So 33 grams of chlorine will combine with 8.37 grams of aluminium. The addition of both makes it 41.37 grams. In this reaction, the whole chlorine will be utilized and only part of the aluminium.
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
the coefficients of a balanced reaction