Stacked end to end I assume.
O=O
Also assume the bond has no length, as it is a double bond.
One oxygen atom has a radius of 73 picometers, or a diameter of 146 picometers, so two in the diatomic molecule have the diameter ( length ) of 292 picometers.
292 picometers/109
= 2.92 X 10 -7 meters per molecule
===========================so,
2.92 X 10 -7 meters per molecule (100 centimeters/1 meter)(1 inch/2.54 centimeters)(1 foot/12 inches)
= 9.58 X 10 -7 feet per molecule
=======================and,
12000 feet/9.58 X 10 -7 feet per molecule
= 1.2526 X 1010 oxygen molecules in that distance
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1 ft = 0.3048 meters (exact conversion ratio, this is a good one to memorize).(12000 ft) * (0.3048 m/ft) = 3657.6 m
There are 2,419.5 square feet in a 12,000 gallon pool if it is 6 feet deep. This can be calculated by converting gallons to cubic feet and then dividing by the depth of the pool in feet.
To convert miles per year to feet per minute, we first convert miles to feet by multiplying by 5280 (1 mile = 5280 feet). Then we convert years to minutes by multiplying by 525600 (1 year = 525600 minutes). Therefore, 12000 miles per year is equivalent to (12000 * 5280) / 525600 = 120.8 feet per minute.
To convert liquid oxygen to gaseous oxygen, you can use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature. Liquid oxygen has a density of about 1.14 g/mL, so one gallon (3.79 L) would be approximately 4.32 kg. Given the conditions (such as pressure and temperature), you can calculate the volume of gaseous oxygen produced.
First, understand the the percent composition of air does not change at 8000 ft. The oxygen, which is what you need to stay alive, is 21% at sea level and at 8000 ft. The density of air is what decreases as you get higher. So even thought at 10,000 feet the air is still 21% oxygen, a given breath of air, contains so few oxygen molecules that you cannot stay mentally alert. Think of a breath of air at 10,000 feet as very dilute air, with lots of empty space between the molecules. Now many jet airplanes pressurize to 8000 feet which is where that number mostly likely came from in the question. The question asks about the percent of air at 8000 feet. If we assume no humidity and we assume temperature of 70 degree ( both those things affect air density so we need to pick some levels and those are reasonable and easy for the calculation) the air density is .0554 lbm/ft3 . The density at 0 feet given the same conditions is .0745lbm/ft3 We can look at the ratio of .0554/.0745 is about 74% so the percent of "air" is about 74% at 8000 feet if we use 0 feet as 100%. If we use 30% relative humidity for both 0 and 8000 feet, the percent does not change. There is a link for calculation air density attached to this answer.
36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd
12000 inches = 1000 feet since 12 inches = 1 foot
3657.6 meters
12,000 feet is 3,657.6 meters.
The radius 1,910 feet.
39370.078740157480315 feet (being too precise)
1 ft = 0.3048 meters (exact conversion ratio, this is a good one to memorize).(12000 ft) * (0.3048 m/ft) = 3657.6 m
There are 12 inches in a foot There are 3 feet in a yard. Therefore there are 36 inches in a yard This means that 12000 inches = (12000/36)=333.3333333333333 yards in 12000 inches.
3.66
39370.07 ft
Because the NH3 molecules have to travel through the nitrogen and oxygen molecules in the atmosphere.
12000 feet