Four.
There are two significant figures in the number 45000.
4.28x10^-3 ------> 4.3x10^-3
No, it actually has seven significant figures. Basic rule: (1)When number has decimal point---count from left to right counting all numbers after the first non-zero number ex.-->.009367 has 4 sig figs ex.-->9.367 has 4 sig figs ex.-->9.367000 has 7 sig figs (2)When number doesn't have a decimal point---count right to left counting all numbers after the first non-zero number ex.-->12 has 2 sig figs ex.-->120 has 2 sig figs ex.-->1207800 has 5 sig figs
12,598,430 inches(Rounded to 7 sig figs, using 1 mi = 1,609.344 m.)
Three * * * * * Numbers ending in 0s before the decimal point are ambiguous. In this case, for example you cannot tell if the number is rounded to the nearest ten (3 sig figs), or to the nearest unit (4 sig figs).
there are 3 sig figs. 4, 0, and 5 are the sig figs
5 sig figs
61 has 2 sig figs.
There are five sig figs
There are four sig figs in 2.905.
There are three sig figs in 1.05.
There are three sig figs in 4890.
All five of them are sig figs
There are two sig figs in 3700000.
There are four sig figs in 1.032
There are four sig figs in 60.55.
There are eight sig figs in 57.115102.