The answer depends on the units of measurement used for the numbers in the question: feet, metres, centimetres, etc.
To determine how many 1.6-inch tiles you need to cover 168 square feet, first convert the tile size to square feet. A 1.6-inch tile is ( \frac{1.6}{12} ) feet, which is approximately 0.1333 feet. The area of one tile is ( 0.1333 \times 0.1333 \approx 0.0178 ) square feet. To find the number of tiles needed, divide the total area by the area of one tile: ( \frac{168}{0.0178} \approx 9444 ) tiles. Thus, you need approximately 9,444 tiles to cover 168 square feet.
Each tile will cover 2 square feet. So you will need 12.5 tiles.
Each tile will cover 2 square feet. You have 64 square feet. You will need 32 tiles.
It takes 4 6x6 inch tiles to cover a square foot. You will need 180 tiles, plus some for spoilage and mistakes.
To determine how many 8x8 tiles are needed for 120 square feet, first calculate the area of one tile. An 8x8 tile has an area of 64 square inches, which is equivalent to 0.4444 square feet (since 144 square inches equals 1 square foot). Dividing 120 square feet by 0.4444 square feet per tile gives approximately 270 tiles needed. Therefore, you would need around 270 tiles to cover 120 square feet.
Tiles that are two feet on a side cover 4 square feet. 378 of them cover 1512 square feet.
192 tiles
76.6 tiles
67 tiles.
190
Two tiles will suffice since they will cover 36 square feet.
500/1.78 = 281 tiles
157 18 by 18 tiles are needed to cover 352 square feet.
start with 38 tiles.
Each tile covers 4 square feet. You will need 24.75 tiles to cover the area.
You will need at least 67 tiles. This will cover 150.75 square feet.
It will require a minimum of 1,462 tiles. That number will cover about 1,850.34 square feet.